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garik1379 [7]
3 years ago
8

The kinetic energy k of an object in joules is given by the formula k=1/2mv² where m is the object's mass in kilograms and v is

its velocity in meters per second. An object’s velocity is 20 meters per second, and its kinetic energy is 48,000 joules. If it speeds up to 40 meters per second, what is its new kinetic energy?
Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

192000 J

Step-by-step explanation:

k = 1/2 mv²

48000 = 1/2 x m x (20)²

48000 = 200m

m = 240 kg

new k

k = 1/2 x 240 x 40²

k = 192000 J

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Of the 50 students in Mr. Mitchell’s classes, 60% are girls. On Friday,20 %
Maurinko [17]

Answer:

6

Step-by-step explanation:

60% of 50 is 30 and 20% of 30 is 6

3 0
3 years ago
The Eastons traveled 190 miles on a trip to Grandma’s house. At the end of the trip the odometer read 7,602 miles. Write and sol
Black_prince [1.1K]

Answer:

X+190=7602

X=7412

Step-by-step explanation:

The odometer read 7412 miles at the beginning of the trip.

3 0
3 years ago
g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len
vredina [299]

Answer:

-\frac{10}{3}ft/s

Step-by-step explanation:

We are given that

Height of man=5 foot

\frac{dy}{dt}=-10ft/s

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

\frac{20}{5}=\frac{x+y}{x}

4=\frac{x+y}{x}

4x=x+y

4x-x=y

3x=y

3\frac{dx}{dt}=\frac{dy}{dt}

\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=-\frac{10}{3}ft/s

7 0
3 years ago
If 5 + 20 times 2^2 minus 3x = 10 times 2^- 2x + 5, what is the value of x?
LUCKY_DIMON [66]
The answer to the problem is going to be 3
4 0
3 years ago
Solve this question ​
love history [14]

Answer:

\frac{4x - 11}{2}  \leqslant 3x - 3 < 4 \\  \\   =  > \frac{4x - 11}{2}  \leqslant 3x - 3 \: and \: 3x - 3 < 4 \\  \\  <  =  > 4x - 11 \leqslant 6x - 6 \:  \: and \:  \: 3x < 7 \\  \\  <  =  > 2x \geqslant  - 5 \:  \: and \:  \: x <  \frac{7}{3}  \\  \\  <  =  >  \frac{ - 5}{2}  \leqslant x <  \frac{7}{3}

=> the greatest integer is 2

the smallest integer is -2

3 0
3 years ago
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