Answer:
No
Explanation:
Virtual and physical metrics have to be collected and analysed to look for allocation problems such as: VM sprawl, too many VMs, or improperly provisioned VMs are occurring.
Answer:
Professionalism means communicating effectively and appropriately and always finding a way to be productive. Employers want new workers to be responsible, ethical, and team oriented, and to possess strong communication, interpersonal, and problem solving skills. Wrap these skills up all together and you've got professionalism.
There are many types of unprofessional behavior in the workplace, which include habitual tardiness, absence, harassment or bringing personal issues to the job. These behaviors can cause disruption to the company as a whole, which means they should be dealt with as soon as possible.
A cloud-first strategy helps this client by providing a data-centric approach that offers more speed, agility, and security. Thus, the correct option is B.
<h3>What is a Cloud-first strategy?</h3>
A cloud-first strategy may be defined as an operational strategy that allows the users to reposition all or most of their infrastructure to cloud-computing platforms.
A cloud-first strategy helps this client in numerous ways. It provides a data-centric approach that offers more speed, agility, and security to its customers or clients in a facilitated manner.
Therefore, the correct option for this question is B.
To learn more about the Cloud-first strategy, refer to the link:
brainly.com/question/24719487
#SPJ1
Answer:
Zebra.
Explanation:
Stack is LIFO, so Zebra is added in the last so it will be removed first.
Answer:
Check the explanation
Explanation:
#!usr/bin/python
#FileName: sieve_once_again.py
#Python Version: 2.6.2
#Author: Rahul Raj
#Sat May 15 11:41:21 2010 IST
fi=0 #flag index for scaling with big numbers..
n=input('Prime Number(>2) Upto:')
s=range(3,n,2)
def next_non_zero():
"To find the first non zero element of the list s"
global fi,s
while True:
if s[fi]:return s[fi]
fi+=1
def sieve():
primelist=[2]
limit=(s[-1]-3)/2
largest=s[-1]
while True:
m=next_non_zero()
fi=s.index(m)
if m**2>largest:
primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers
break
ind=(m*(m-1)/2)+s.index(m)
primelist.append(m)
while ind<=limit:
s[ind]=0
ind+=m
s[s.index(m)]=0
#print primelist
print 'Number of Primes upto %d: %d'%(n,len(primelist))
if __name__=='__main__':
sieve()
