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Stolb23 [73]
3 years ago
12

The picture. and answer 1-6. please hurry

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

From the figure attached,

1). Sin(D) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

2). Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

                = \frac{ED}{DF}

                = \frac{10}{26}

                = \frac{5}{13}

3). tan(D) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{EF}{DE}

               = \frac{24}{10}

               = \frac{12}{5}

4). sin(F) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

              = \frac{DE}{DF}

              = \frac{10}{26}

              = \frac{5}{13}

5). cos(F) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

6). tan(F) = \frac{\text{Adjacent side}}{\text{Adjacent side}}

               = \frac{DE}{EF}

               = \frac{10}{24}

               = \frac{5}{12}

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Answer:

The lines are perpendicular

Step-by-step explanation:

we have

2x+y=4

isolate the variable y

y=-2x+4 ----> equation A

The slope of the line A is m=-2

y=\frac{1}{2}x+4 -----> equation B

The slope of the line B is m=\frac{1}{2}

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

In this problem

The slopes of line A and line B are opposite reciprocal

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An airplane descended 4,000 feet before landing. The integer that represents how many feet the airplane was above the ground bef
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Answer:

Since, an airplane descended 4,000 feet before landing.

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Before the descent, airplane was at the height of 4,000 feet.

And the distance above the ground is represented by the positive integers and distance below the ground is represented by the negative integers.

Since, 4,000 feet is the distance of airplane above the ground.

So, the airplane was +4,000 feet above the ground before its descent.

8 0
4 years ago
In 3x² - x + 5 = 0, what is the quadratic term
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You’ve bought a half-dozen (six) eggs from the store but you forgot to check them first! The probability that no eggs are broken
GREYUIT [131]

Answer:

a)

P(X = 0) = C_{6,0}.(0.1416)^{0}.(0.8584)^{6} = 0.4

P(X = 1) = C_{6,1}.(0.1416)^{1}.(8584)^{5} = 0.3960

P(X = 2) = C_{6,2}.(0.1416)^{2}.(8584)^{4} = 0.1633

P(X = 3) = C_{6,3}.(0.1416)^{3}.(8584)^{3} = 0.0359

P(X = 4) = C_{6,4}.(0.1416)^{4}.(8584)^{2} = 0.0044

P(X = 5) = C_{6,5}.(0.1416)^{5}.(8584)^{1} = 0.0003

P(X = 6) = C_{6,6}.(0.1416)^{6}.(8584)^{0} = 0.00001

b) 56.77% probability that an even number of eggs is broken.

c)

Expectation: 0.8496

Variance: 0.7293

Step-by-step explanation:

For each egg, there are only two possible outcomes. Either it is broken, or it is not. The probability of an egg being broken is independent from other eggs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The variance of the binomial distribution is:

V(X) = np(1-p)

There are 6 eggs

So n = 6

The probability that no eggs are broken is 0.4.

This means that P(X = 0) = 0.4. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.p^{0}.(1-p)^{6}

(1 - p)^{6} = 0.4

Taking the sixth root from both sides of the equality

(1 - p) = 0.8584

p = 0.1416

Each egg has a 0.1416 probability of being broken

(a) Write out the pmf of X.

Probability of each value, from 0 to 6

P(X = 0) = C_{6,0}.(0.1416)^{0}.(0.8584)^{6} = 0.4

P(X = 1) = C_{6,1}.(0.1416)^{1}.(8584)^{5} = 0.3960

P(X = 2) = C_{6,2}.(0.1416)^{2}.(8584)^{4} = 0.1633

P(X = 3) = C_{6,3}.(0.1416)^{3}.(8584)^{3} = 0.0359

P(X = 4) = C_{6,4}.(0.1416)^{4}.(8584)^{2} = 0.0044

P(X = 5) = C_{6,5}.(0.1416)^{5}.(8584)^{1} = 0.0003

P(X = 6) = C_{6,6}.(0.1416)^{6}.(8584)^{0} = 0.00001

(b) Compute the probability that an even number of eggs is broken.

0, 2, 4 or 6

P = P(X = 0) + P(X = 2) + P(X = 4) + P(X = 6) = 0.4 + 0.1633 + 0.0044 + 0.00001 = 0.5677

56.77% probability that an even number of eggs is broken.

(c) Compute the expectation and variance of X.

Expectation:

E(X) = np = 6*0.1416 = 0.8496

Variance:

V(X) = np(1-p) = 6*0.1416*0.8584 = 0.7293

7 0
4 years ago
there were some people on a train. 19 people get off the train at first stop.17 people get on the train.now there are 63 people
sdas [7]
Let the people initially on the train be 'x'.


19 people got off the train --> x - 19

17 people got on the train --> x - 19 + 17


Remaining people on the train = 63

Therefore, x - 19 + 17 = 63
                  x - 2 = 63
                       x = 63 + 2
                       x = 65

Verification:
65 - 19 + 17 = 63
65 - 2 = 63
63 = 63
--------------------------------------------------
Hope I helped!
5 0
4 years ago
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