Answer:
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Question
When <u>6</u><u> </u><u>times</u><u> </u><u>a</u><u> </u><u>number</u><u> </u> is increased by 11 the result is 16 less than 9 times the number. Find the number.
Answer · 7 votes
Answer:6x+11=9x-163x=27X=9 Please mark it brainliest
Step-by-step explanation:
Please mark it brainliest
Answer:
18,176
Step-by-step explanation:
Figure out an easier thing to do: 1000 - 2021 = 9,797.
Therefore, our answer will be like 9999999999999999999999997979. Out of all of these digits, there are only 2 that arent nines. We know the amount of digits since it's 10^2021 power. We will have one less since we are subtracting 2021. Therefore, 2020 digits in total. Now we know of those 2020 digits, 2 of them are 7, therefore 2018 of them are 9s. That means do 2018(9) + 2(7) = 14 + 18,162 = 18,176.
2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1 5/12
1 + 5/12 = 12/12 + 5/12 = 17/12 = 1 5/12
2/3 + 3/4 = 1 + 5/12
Answer:
Associative property of multiplication.
Step-by-step explanation:
Answer:
We know that:
She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)
She only has 1/3 of the amount she needs.
How much flour does she have?
Well, she needs 9/10 grams, and she has one-third of that.
Then she has (1/3) times (9/10) grams, this is:
F = (1/3)*(9/10) grams
F = (1*9)/(3*10) grams
F = 9/30 grams
That is the amount of flour that she has.
