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olasank [31]
2 years ago
14

A football team lost a total of 2 1/2 yards in 5 plays. What was the average change in yardage per play?

Mathematics
1 answer:
leonid [27]2 years ago
6 0

Answer:

0.5 yards

Step-by-step explanation:

average change in yardage per play = total yards / number of plays

2.5 yards / 5 = 0.5 yards

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Find the third side in simplest radical form <br> can anybody help me with this please!
Katyanochek1 [597]

Answer:

sqrt(98) aka \sqrt{98}

Step-by-step explanation:

To find the third side we need to use the Pythagorean theorem (a^2 + b^2 = c^2)  so let 3 = a and b = sqrt(89) so a^2 = 9 and for b^2 just ignore the square root so b^2 = 89 then we add 9 and 89 89 + 9 = 98 so c^2 = 98 then we do the square root of 98 since the square root of 98 isn't a whole number/ has a decimal we just leave it written as sqrt(98)

8 0
3 years ago
It takes 12 men 8 days to construct a wooden shed. How many days will 15 men take?
Fynjy0 [20]

Answer:

10 days.

Step-by-step explanation:

8÷12 (because you can not divide people.

.666

take that and multiply it by 15

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6 0
3 years ago
The length of a rectangle is 6 inches longer than it’s width what are the possible widths if the area of the rectangle is at lea
stealth61 [152]

Let the width = x

length = x + 6

(x + 6) * x = 667

Simplify

x² + 6 = 667

x² + 6 (-6) = 667 (-6)

x² = 661

√x² = √661

x = √661

x = 25.71 (rounded)

25.71 in. is your width

hope this helps

6 0
2 years ago
(08.06 MC)
const2013 [10]

Answer:

  (3.5, 17)

Step-by-step explanation:

It would be nice to see the whole graph, so we can see where the functions cross.

Without that information, we can still eliminate unreasonable choices.

A) the quadratic at y=3.5 is well above the exponential

B) the most likely choice (3.5, 17)

C) at x=-8, the quadratic is above the exponential

D) neither graph goes anywhere near y = -8

8 0
3 years ago
Read 2 more answers
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slavikrds [6]
<span>C. (4,3)

Draw and plot on a graph and (4,3) could be the other end point, which
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y > 2</span>
6 0
3 years ago
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