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4 years ago

If ABCD is a parallelogram, BC =3m + 10, and AD = 7m – 2, find the value of ‘m’. *

Mathematics

1 answer:

-BARSIC- [3]4 years ago

8 0

Answer:

The value of m is 3

Step-by-step explanation:

We are given that ABCD is a parallelogram

Property of parallelogram : Opposite sides of parallelogram is equal

So, AB = CD and BC = AD

We are given that

BC =3m + 10

AD = 7m – 2

So, Using Property

BC=AD

3m+10=7m-2

12=4m

$\frac{12}{4}=m$

3=m

Hence The value of m is 3

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at the market, a housewife bought 2 kilograms of eddoes at $5 per kilogram and 5 kilograms of chicken at $10 per kilogram. she p

madam [21]

Answer:

The total for the housewife's purchase should be 60 dollars. So it should be the vender who owes her money. The vender owes her 15 dollars.

Step-by-step explanation:

$5 = 1kg (eddoes) meaning a total of 2kg eddos =$10

$10 = 1kg (chicken) meaning a total of 5kg chicken = $50

When added together, it'd be 60 dollars.

(I'm not sure if you maybe forgot a part of the question or only had this part)

4 0

3 years ago

What is the approximate diameter of a tire that will make 775 complete rotations in one mile? (Note: there are 5280 feet

GalinKa [24]

Answer:

About 2.17 feet.

Step-by-step explanation:

Let d represent the diameter of the tire.

Then the circumference of the tire will be:

$C=d\pi$

So, the tire will travel dπ miles after one rotation.

After 775 rotations, the total miles traveled should be 5280 feet. Thus:

$775(d\pi)=5280$

Solve for d:

$\displaystyle d=\frac{5280}{775\pi}$

Approximate:

$d=2.1686...\approx2.17$

The circumference of the tire should be about 2.17 feet.

5 0

3 years ago

An archaeologist at a dig sets up a coordinate system using string. Two similar artifacts are found one at position (1, 4) and t

myrzilka [38]

Given:

Positions of two artifacts are at points (1, 4) and (5, 2).

To find:

The distance between these two artifacts.

Solution:

Distance formula: The distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, the distance between two points (1, 4) and (5, 2) is

$d=\sqrt{(5-1)^2+(2-4)^2}$

$d=\sqrt{(4)^2+(-2)^2}$

$d=\sqrt{16+4}$

$d=\sqrt{20}$

$d=4.4721359$

Round to the nearest tenth of a unit.

$d\approx 4.5$

Therefore, the distance between two artifacts is 4.5 units.

4 0

3 years ago

In ΔTUV, the measure of ∠V=90°, the measure of ∠U=70°, and UV = 9.6 feet. Find the length of TU to the nearest tenth of a foot.

Nutka1998 [239]

28.1 feet

explaination

\cos U = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{9.6}{x}

cosU=

hypotenuse

adjacent

=

x

9.6

\cos 70=\frac{9.6}{x}

cos70=

x

9.6

x\cos 70=9.6

xcos70=9.6

Cross multiply.

\frac{x\cos 70}{\cos 70}=\frac{9.6}{\cos 70}

cos70

xcos70

=

cos70

9.6

Divide each side by cos 70.

x=\frac{9.6}{\cos 70}=28.0685\approx 28.1\text{ feet}

x=

cos70

9.6

=28.0685≈28.1 feet

Type into calculator and roundto the nearest tenth of a foot.

8 0

3 years ago

Find the circumference of a circle that has a 25-inch radius. Use 3.14 to approximate π.

Sergio [31]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
➣ Circumference:- The line that bounds a circle or other two-dimensional figure

${ \rule{70mm}{2.9pt}}$

★ also circumference of a circle is also known as it's perimeter

➣To find circumference of circle when use formula

${ \boxed{✜\underline{ \boxed{ \sf{\: Circumference \: of \: circle= \: 2\pi \: r}}}✜}}$

➢ r = radius (25inch.)
➢ value of π is 3.14

${ \rule{70mm}{2.9pt}}$

$\large\underline{ \boxed{ \sf{✰\: Let's\:solve }}}$

$\sf{➛ \: Circumference \: of \: circle = 2 \times 3.14 \times 25} \\ \sf{➛ \: Circumference \: of \: circle =2 \times 78.5} \\ \sf{➛ \: Circumference \: of \: circle =157inch}$

★ Hence circumference of circle=157inch

$\large\underline{ \boxed{ \sf{➪\:157inch. }}}$

${ \rule{70mm}{2.9pt}}$

Hope it helps !

4 0

2 years ago