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Flauer [41]
3 years ago
13

PLS HELP ME AyO HELP LOL OLOLOLOLOLOlOLO(l9 BRUH

Mathematics
2 answers:
QveST [7]3 years ago
7 0
0.75 or 3/4 that’s your answer as a decimal and fraction :)
Levart [38]3 years ago
4 0

Answer:

3 i think

Step-by-step explanation:

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Rachel has developed a plan to start paying off her credit card debt, and has stopped making purchases with her credit card. She
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Present value of annuity PV = P(1 - (1 + r/t)^-nt) / (r/t)
where: p is the monthly payment, r is the APR = 14.12% = 0.1412, t is the number of payments in one year = 12, n is the number of years = 2.
1,120.87 = P(1 - (1 + 0.1412/12)^(-2 x 12)) / (0.1412 / 12)
0.1412(1120.87) = 12P(1 - (1 + 0.1412/12)^-24)
P = 0.1412(1120.87) / 12(1 - (1 + 0.1412/12)^-24) = $53.88

Minimum monthly payment = 3.15% of 1120.87(1 + 0.1412/12) = 0.0315 x 1120.87(1 + 0.1412/12) = $35.72

Therefore, his first payment will be greater than the minimum payment by 53.88 - 35.72 = $18.16
5 0
3 years ago
Read 2 more answers
Which of the following is considered a
Mariulka [41]

Answer:

C

Step-by-step explanation:

Students loan as it's money owed to a supplier.

8 0
2 years ago
If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different
irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
Solve for x.<br> 9(x+1)=25+x<br> x=2<br> 0x=3<br> O x=4<br> O x=5
aleksandr82 [10.1K]

Step-by-step explanation:

9(x+1) = 25+x

open the bracket

9x + 9 = 25+x

collect like terms

9x-x = 25-9

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3 0
2 years ago
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