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VARVARA [1.3K]
3 years ago
15

How do you work out this math problem?? 2+2x-5=5(x+3)

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0
1) Simplify the problem

This involves combining variables

2-5=-3

Now that is -3+2x= 5x+15

2) Find the hidden variable.

Now that the problem is in order you can find the hidden variable of x.

So think what number in place of x makes this equation true?

There are may ways you can solve for x, including the substitution method.
exis [7]3 years ago
3 0
The first step i'd take is distributing the right side, by multiplying everything in the parentheses by 5 , so ; 2+2x-5=5x+15

then you could gather similar or like terms on one side, by moving all the x terms to the right, and all the regular terms to the left. to do this, you do the same thing on both sides of the equation

 2 +2x -5   = 5x +15      
    -2x -15 = -2x -15

2-5-15 = 3x
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3 years ago
Solve the formula A=12bh for h when A=90 and b=15. Write the answer in decimal form.
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Given,

A=90

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A=12bh

Now,

Step-by-step explanation:

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A=12bh

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4 0
3 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

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3 years ago
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