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marshall27 [118]
3 years ago
13

Two hot air balloons are traveling along the same path away from a town,

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.

Step-by-step explanation:

The distance of Tasha's balloon from the town is represented by the function y = 8x+ 20 ............. (1)

Where y is the distance in miles from the town and x represents the time of fly in hours.

So, at the start of the journey i.e. at x = 0, y = 20 miles {From equation (1)} from the town.

Again, Tasha's balloon is traveling at a rate of 8 miles per hour.

Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.

So, Henry's balloon traveling with the speed of  miles per hour.

Therefore, Henry's balloon was farther from the town at the beginning i.e. 30 miles from the town. And Henry's balloon traveled more quickly i.e at the rate of 9 miles per hour. (Answer)

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\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta
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Internal validity

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Step-by-step explanation:

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