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2 years ago

6

Which of the following would be the best method for investigating the correlation between the hibernation habits of bears and th

e temperature for 90 days prior to their hibernation?
A. Survey
B. Observational study
C. Randomized experiment
D. Experimental study

1 answer:

Andre45 [30]2 years ago

4 0

Answer: Observational study

Step-by-step explanation: I just took the test

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

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2 years ago

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What is 2,168.433 rounded to the nearest mile?

olga nikolaevna [1]

Answer:

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2 years ago

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Tolong bantu jawab yaa PAKAI CARAA

yanalaym [24]

B? <span>

1 2/3 </span><span>÷ 1 1/9 = 1.5

2.34 </span><span>÷ 0.6 = 3.9</span>

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3 years ago

What is -1/19,7/4,-4/7 in least to greatest

r-ruslan [8.4K]

Answer:

-4/7 is the smallest. then it's -1/19 and then finally it's 7/4

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Consider the figure.<br> What is JL?

lisov135 [29]

The answer for the above mentioned problem is JL = 12.5

Step by step explanation:

Given:

JM = 8

KM = 6

To Find:

JL = ?

Formula to be used:

$KM^2$ = JM x ML

In order to find " JL" we must first find "ML",

$KM^2$ = JM x ML

$6^2$ = 8 x ML

36 = 8 x ML

36/8 = ML

ML = 4.5

Now JL = 4.5+8

= 12.5

Thus the value of JL = 12.5

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2 years ago