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blondinia [14]
3 years ago
9

_384 What is the square root of 384

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

19.5959179423

Step-by-step explanation:

Illusion [34]3 years ago
5 0

Answer: ≈ 20

19.5959179423

Explanation:

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Step-by-step explanation:

3 0
3 years ago
To convert 58.58 to a fraction, we evaluate 58.58-0.58 What is 58.58-0.58 ?
lord [1]

Answer:

58

Step-by-step explanation:

58.58 - 0.58 = 58

4 0
4 years ago
Read 2 more answers
HELP
dsp73

Answer:

1)  4

2) 3

3) 9

4) 6

5) 3/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
8 - (7/10)t = 6 - (1/5)t
rosijanka [135]

Answer:

t = 4

Step-by-step explanation:

Solve for t:

8 - (7 t)/10 = 6 - t/5

Hint: | Put the fractions in 8 - (7 t)/10 over a common denominator.

Put each term in 8 - (7 t)/10 over the common denominator 10: 8 - (7 t)/10 = 80/10 - (7 t)/10:

80/10 - (7 t)/10 = 6 - t/5

Hint: | Combine 80/10 - (7 t)/10 into a single fraction.

80/10 - (7 t)/10 = (80 - 7 t)/10:

1/10 (80 - 7 t) = 6 - t/5

Hint: | Put the fractions in 6 - t/5 over a common denominator.

Put each term in 6 - t/5 over the common denominator 5: 6 - t/5 = 30/5 - t/5:

(80 - 7 t)/10 = 30/5 - t/5

Hint: | Combine 30/5 - t/5 into a single fraction.

30/5 - t/5 = (30 - t)/5:

(80 - 7 t)/10 = (30 - t)/5

Hint: | Make (80 - 7 t)/10 = (30 - t)/5 simpler by multiplying both sides by a constant.

Multiply both sides by 10:

(10 (80 - 7 t))/10 = (10 (30 - t))/5

Hint: | Cancel common terms in the numerator and denominator of (10 (80 - 7 t))/10.

(10 (80 - 7 t))/10 = 10/10×(80 - 7 t) = 80 - 7 t:

80 - 7 t = (10 (30 - t))/5

Hint: | In (10 (30 - t))/5, divide 10 in the numerator by 5 in the denominator.

10/5 = (5×2)/5 = 2:

80 - 7 t = 2 (30 - t)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

80 - 7 t = 60 - 2 t

Hint: | Move terms with t to the left hand side.

Add 2 t to both sides:

2 t - 7 t + 80 = (2 t - 2 t) + 60

Hint: | Look for the difference of two identical terms.

2 t - 2 t = 0:

2 t - 7 t + 80 = 60

Hint: | Group like terms in 2 t - 7 t + 80.

Grouping like terms, 2 t - 7 t + 80 = 80 + (2 t - 7 t):

80 + (2 t - 7 t) = 60

Hint: | Combine like terms in 2 t - 7 t.

2 t - 7 t = -5 t:

-5 t + 80 = 60

Hint: | Isolate terms with t to the left hand side.

Subtract 80 from both sides:

(80 - 80) - 5 t = 60 - 80

Hint: | Look for the difference of two identical terms.

80 - 80 = 0:

-5 t = 60 - 80

Hint: | Evaluate 60 - 80.

60 - 80 = -20:

-5 t = -20

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -5 t = -20 by -5:

(-5 t)/(-5) = (-20)/(-5)

Hint: | Any nonzero number divided by itself is one.

(-5)/(-5) = 1:

t = (-20)/(-5)

Hint: | Reduce (-20)/(-5) to lowest terms. Start by finding the GCD of -20 and -5.

The gcd of -20 and -5 is -5, so (-20)/(-5) = (-5×4)/(-5×1) = (-5)/(-5)×4 = 4:

Answer: t = 4

6 0
3 years ago
A superintendent of schools wonders if scores on a test of science achievement differ for female and male 8th grade students. To
lina2011 [118]

Answer:

b. 2-independent sample t-test

Correct for this case is the best test since the result from each group are independent and we can compare the sample means between th two groups

Step-by-step explanation:

For this case the intention is try to test if scores on a test of science achievement differ for female and male 8th grade students. let's analyze the possible options for this case:

a. 2-dependent sample t-test

False is not possible since the nature of the gender is not possible to conclude tha the results from boys and girls are dependent

b. 2-independent sample t-test

Correct for this case is the best test since the result from each group are independent and we can compare the sample means between the two groups

c. Correlation

False we can't compare the means of interest with a correlation coefficient since that's not the purpose of the study

d. 2-way ANOVA

False we have just one variable between two groups so is not possible to apply a 2 way ANOVA

5 0
3 years ago
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