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slamgirl [31]
2 years ago
12

17. According to the Associative Property, which expression is equal to (12)(7)(6x)?

Mathematics
2 answers:
Dvinal [7]2 years ago
5 0

(12)(7)(6x)=504x

(12 * 7 * 6)(x)=504x

(7)(12)(6) + x=504+x

12(7 + 6x)=84+72x

12 + 7 + 6x=19+x

wee see that

A*B=(A)(B)


Verdich [7]2 years ago
4 0
I believe the expression equals to 12(7+6x). You multiply 12 by everything but you can't multiply the x to everything so Itd be 84+72x. answer being C.
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joja [24]

Answer:

55.5 u^2

Step-by-step explanation:

Split the quadrilateral into 2 triangles. There are two ways to do this, but I'm only doing one of them.

On the 5-11 triangle, use the two of the lengths and plug them into the triangle area formula. (L x W)/2 = A

5-11 triangle area: 27.5

Do the same for the 7-8 triangle. Plug it into the same formula.

7-8 triangle area: 28

Add the two areas. 27.5 + 28 = 55.5

8 0
3 years ago
Please please help!!
sweet-ann [11.9K]

Answer:

4

Step-by-step explanation:

12/2=6

20/2=10

10-6=4

7 0
2 years ago
1. What is the solution of n² – 49 = 0? (1 point)
maks197457 [2]

Answer:

1. n=\pm7

2. x=\pm7i[tex]3.[tex]\pm 12x =a

4. 22

Step-by-step explanation:

1. n^2 - 49 = 0

n^2 =49

n= \sqrt{49}

n=\pm7

2. x^2+64 = 0

x^2 =-64

x= \sqrt{49}

x=\pm7i[tex]3. Area of square = [tex]a^{2}

Where a is the side

We are given an area o square = 144x^{2}

So, 144x^{2}=a^{2}

\sqrt{144x^{2}}=a

\pm 12x =a

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

(x+9)(x-9)=0

x^2- 81=0

So, in the given equation x^2 + z = 103

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

x^2 + 22 = 103

x^2 + 22 -103=0

x^2 -81=0

Thus the value of z is 22

8 0
3 years ago
Read 2 more answers
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
HELP MUST BE DONE BY 4:00
Leya [2.2K]

Answer:

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8 0
2 years ago
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