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3 years ago

10

DISNEY HAS 16 MOVIES THAT ARE ELIGIBLE FOR THE DISNEY VAULT. 62.5% OF THE MOVIES ARE AVAILABLE FOR THE SALE. HOW MANY VAULT MOVI

ES CAN YOU CURRENTLY BUY?

1 answer:

Norma-Jean [14]3 years ago

8 0

You can buy 26 movies

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50 POINTS!!Different project management steps are initiating, planning, executing, monitoring and controlling, and closing a pro

garri49 [273]

Answer: Planning because you need to start somewhere if you dont then you dont have any of the other steps

Good luck lovie :)

8 0

3 years ago

Please come answer ASAP!!!<br> 5 - n divided by 3 = 4 what is the value of n?

Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

-n = -27

Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

7 0

3 years ago

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

Five less than the area of a square is 59 square feet. Find the side length of the square.

In-s [12.5K]

Answer:

4 feet

Step-by-step explanation:

Let the side length of the square be x feet.

x^2 - 5 = 59

x^2 = 64

x = ±4 (reject - 4 since length > 0)

Topic: Areas of polygons

If you would like to venture further, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

6 0

3 years ago

Helpppppppppppppp please

Bingel [31]

Answer:29

so the mini triangle in the corner is a mini model of the entire triangle, all you have to do is take the width or bottom number and find the factor in which it is smaller, then take the height of the smaller triangle and add the factor in which it increases to it. so the factor goes up by 31 1/2--9=22 1/2 and adding the factor in which it increases to the height is 22 1/2+6 1/2=29 because 2 halfs make a whole.

Step-by-step explanation:

mr clean has big brien 0-0

5 0

3 years ago

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