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3 years ago

Given: ∠1 and ∠2 are complementary angles.Prove: ∠3 and ∠4 are complementary angles.

Mathematics

2 answers:

ASHA 777 [7]3 years ago

4 0

Answer:

Two angles are called complementary when their measures add to 90 degrees. ∠1 is 60 degrees ∠2 is 30 degrees so if you add it up, the answer is 90 degrees.

∠4 + ∠3 = answer has to be 90 degrees to call it a complementary angle

30 degrees + 60 degrees = 90 degrees

Gennadij [26K]3 years ago

3 0

Answer:

If I had to pick between these, it would be definition of complementary angles.

Hope this helps!

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The set of all output values y in a function is called the ___ of the function

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Range of a function.

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4 years ago

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Suppose that a data set has a mean of 4400. An outlier with a value of 10 is added to the data set. What affect would this outli

Aleks04 [339]

With such a high mean an outlier that is of the value of ten would cause the mean of the data set to decrease.

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Solve the system of equations below<br>5x+2y=9<br>2×-3y=15<br>

nirvana33 [79]

Answer:

The solution is (3, -3)

Step-by-step explanation:

5x + 2y = 9

2x - 3y = 15

Use elimination by addition/subtraction. Multiply the first equation by 3 and the second by 2, obtaining:

15x + 6y = 27

4x - 6y = 30

----------------------

19x = 57

This yields x = 3.

Substituting 3 for x into 5x + 2y = 9, we get 5(3) + 2y = 9, or

15 + 2y = 9, or

2y = -6

This yields y = -3.

The solution is (3, -3)

4 0

3 years ago

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago

Find the value of x. 2(3x - 5) = 8

aliina [53]

Answer:

Step-by-step explanation:

2(3x - 5) =8

6x - 10 =8

6x =8 +10

6x =18

x=18 :6

x=3

4 0

3 years ago