The sum of the two smaller sides must be greater than longest side.
A) 3+2 > 7 ..... False
B) 6+10 > 14 ... True
C) 3+2 > 5 ....False
D) 23+18 > 42 ....False
Answer is B
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
B. -9 is the most negative one, -2 is the least.
Hope this helps you.
0.67, because when you have a percent like that you just need to move the decimal 2 places to the left.
Answer: y = 2x + 5
Step-by-step explanation:
