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marta [7]
3 years ago
14

Find the unknown digit to make each statement true 3.59 > 3.5 1 >3.572

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

The unknown digit here is 8

3.59 > 3.5<u>8</u>1 >3.572

The numbers given are up to 3 decimal places.

Since the unit's digit and the tenth digit of all the three numbers are same, the the centre number needs to be < 9 and > 7 for the condition to be satisfied.

Hence, the centre number can only be 8.

Softa [21]3 years ago
6 0

We are given statement 3.59 > 3.5__1 >3.572.

We have a blank space in between 5 and 1 in the middle number given.

Given statement ccan be read as :

3.59 is greater than 3.5__1 is greater than 3.572.

So, we need to check a number that is less than 3.59 but less than 3.572.

The hundredth place of 3.59 number is 9 and

hundredth place of 3.572 number is 7.

So, we need to find a number between 7 and 9.

8 is the number in between 7 and 9.

So, the known digit can be replaced by 8 to make the statement true.

And final statement is 3.59 > 3.581 >3.572.

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B

Step-by-step explanation:

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Alecsey [184]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Use the substitution method to solve each linear system. 4x - 3y = -13,-2x + y = 4
Contact [7]

Answer:

The solutions to the system of equations are:

x=\frac{1}{2},\:y=5

Step-by-step explanation:

Given the system of the equations

\begin{bmatrix}4x-3y=-13\\ -2x+y=4\end{bmatrix}

Isolate x for for 4x-3y=-13

4x-3y=-13

4x=-13+3y

Divide both sides by 4

x=\frac{-13+3y}{4}

substitute y=5

x=\frac{-13+3\cdot \:5}{4}

x=\frac{1}{2}

The solutions to the system of equations are:

x=\frac{1}{2},\:y=5

8 0
2 years ago
A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the
zlopas [31]
1. The function h(t)=-16t^{2}+48t is a parabola of the form ax^{2}+bx. The the formula for the axis of symmetry of a parabola is x= \frac{-b}{2a}. We can infer from our function that a=-16 and b=48, so lets replace those values in our formula:
x= \frac{-b}{2a}
x= \frac{-48}{-2(16)}
x= \frac{-48}{-32}
x= \frac{3}{2}
x=1.5
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
0=-16t^{2}+48t
-16t(t-3)=0
t=0 or t-3=0
t=0 or t=3
From our previous point we know that the ball reaches its maximum time at t=1.5, which means that <span>it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>

7 0
3 years ago
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y = Acos(Bx) + D;

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WE get y = 2cos(16/5x) + 4

4 0
2 years ago
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