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kogti [31]
2 years ago
11

Can anyone help me?.

Mathematics
1 answer:
4vir4ik [10]2 years ago
7 0
The third one is the correct answer
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Hey i will give free brainlest who wants them then come take some brainliests
suter [353]

Answer:

me bro i need points mark me

8 0
3 years ago
Read 2 more answers
That sounds like a good deal, but how about I give you 10 points for an answer.
Ilia_Sergeevich [38]
The answer is A - 1
Hope it helped
3 0
2 years ago
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a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. In y
bekas [8.4K]
F(x) = 2^x; h(x) = x^3 + x + 8

Table


x      f(x) =  2^x             h(x) = x^3 + x + 8

0      2^0 = 1                0  + 0 + 8 = 8

1     2^1 = 2                 1^3 + 1 + 8 = 10

2      2^2 = 4                2^3 + 2 + 8 = 8 + 2 + 8 = 18

3      2^3 = 8                3^3  + 3 + 8 = 27 + 3 + 8 = 38

4      2^2 = 16              4^3 + 4 + 8 = 76

10    2^10 = 1024       10^3  +10 + 8 = 1018

 9      2^9 =   512        9^3 + 9 + 8 = 729 + 9 + 8 = 746

Answer: an approximate value of 10
7 0
3 years ago
How can I find c in a=3 b=4
Dahasolnce [82]
A^2+b^2= c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c
8 0
3 years ago
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