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kogti [31]
2 years ago
11

Can anyone help me?.

Mathematics
1 answer:
4vir4ik [10]2 years ago
7 0
The third one is the correct answer
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Suppose that 10 people, including you and a friend, line up for a group picture. How many ways can the photographer rearrange th
slamgirl [31]

Answer:

483 840 ways

Step-by-step explanation:

Let you and your friend be A and B.

With three people always between you two,, we have

Case 1: AxxxBxxxxx

Case 2: xAxxxBxxxx

Case 3: xxAxxxBxxx

Case 4: xxxAxxxBxx

Case 5: xxxxAxxxBx

Case 6: xxxxxAxxxB

So there is 6 ways of arranging you two through the line and for each of the six cases,

If you two remained in your positions, the rest can be arranged in 8! ways

Also for each case, you two can interchange your positions in 2! ways

Therefore,

The photographer can rearranged the line keep three people between you an your friend in

8! * 2! * 6 = 483 840 ways

7 0
2 years ago
If P(x) = 0.35, find the complement
katovenus [111]
Hello : 
P(x) + P(x') =1   ...( x' is the <span>complement of x)
0.3 +</span> P(x') =1
 P(x') = 1 - 0.3 = 0.7
4 0
3 years ago
The total sales of a company​ (in millions of​ dollars) t months from now are given by .
nydimaria [60]

Answer:

A. find

Step-by-step explanation:

it helps you

8 0
2 years ago
Javier is cooling a liquid in a science lab. The liquid starts at 85 degrees, and he cools it 3.5 degrees every minute for 12 mi
bija089 [108]
85- (3.5*12)

* means times


I think this is correct.
7 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
Read 2 more answers
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