The answer is D. Think back to the quadratic formula
You would plug in values of a, b, and c to find the zeros of the equations. It would the same way in a spreadsheet program where the cells contain the a, b, and c values but you can have more values and a different equation.
Answer:
B)-4
Step-by-step explanation:
y=mx+c
sub in a point and gradient/slope to get c
-7=3(-1)+c
-7=-3+c
-7+3=c
c=-4
y=3x-4
if u looking for the y intercept make x=0
y=3(0)-4
y=-4
Oh boy, here we go again
First we must convert 1 2/3 to an improper fraction. By doing this, we get 5/3 (3/3 + 2/3)
So now we have 273 / 5/3
To divide this easier we can do something that when I learned it was called (keep, change, flip) which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction
This now turns into: 273/1 * 3/5
Combine 273 and 3/5
273⋅3/5
Multiply 273
by 3
819/5
is your answer
Anser is B). Subtract smallest number
