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AleksandrR [38]
4 years ago
9

What integer and-8 have the product of -96

Mathematics
2 answers:
laiz [17]4 years ago
7 0
That would be 12
12 times -8 = -96!

:) Have a nice day and maybe consider grading this answer brainliest? <3
Ratling [72]4 years ago
3 0
Your answer is 12. 

12 * (- 8) = - 96. 
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4 0
4 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
I’m having trouble answering e,f, and g
kodGreya [7K]
What’s is it about can you tell me.?
4 0
4 years ago
Read 2 more answers
Plzzz help plzzzzzzzzzzzzzz
mezya [45]

Given:

The figure of two quadrilaterals.

In ABCD,AB=18,BC=20,CD=22,AD=24

In EFGH,EF=27,FG=30,GH=34, EH=36

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

\dfrac{AB}{EF}=\dfrac{18}{27}

\dfrac{AB}{EF}=\dfrac{2}{3}

Similarly,

\dfrac{BC}{FG}=\dfrac{20}{30}

\dfrac{BC}{FG}=\dfrac{2}{3}

\dfrac{CD}{GH}=\dfrac{22}{34}

\dfrac{CD}{GH}=\dfrac{11}{17}

And,

\dfrac{AD}{EH}=\dfrac{24}{36}

\dfrac{AD}{EH}=\dfrac{2}{3}

Clearly, \dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}.

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0
3 years ago
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