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3 years ago

9

On a scale drawing of Princeton, two landmarks are shown 2 centimeters apart. If the scale of the map is 1 centimeter : 35 kilom

eters, then what is the actual distance between the two landmarks?

1 answer:

tankabanditka [31]3 years ago

3 0

Answer:

70 km

Step-by-step explanation:

2 cm is twice as much as 1 cm. So, the distance between landmarks will be twice as much as 35 km.

The actual distance is 70 km.

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fgiga [73]

Answer:

A. y = 0.5(2)^x

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0 .

Horizontal Asymptote:

y = 0

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2 years ago

If f(x)=8-10x and g(x) =5x +4, what is the value of (fog)(-2)?

swat32

Answer:

68

Step-by-step explanation:

Any function is evaluated by putting the argument value where the variable is, then doing the arithmetic. When the argument is another function value, that function value is evaluated first.

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<h3>f∘g</h3>

The "o" in (fog) is a stand-in for the "ring operator" (∘) which is the operator used to signify a composition. A composition is evaluated right-to-left. That means (f∘g)(x) ≡ f(g(x)). The value of g(x) is found first, and is operated on by the function f.

Writing the composition in the form f(g(x)) lets you identify the layers of parentheses. As with any expression evaluation, the Order of Operations applies. It tells you to evaluate the expression in the innermost parentheses and work your way out.

<h3>g(-2)</h3>

To evaluate (f∘g)(-2) = f(g(-2)), we must first evaluate g(-2). That is ...

g(x) = 5x +4

g(-2) = 5(-2) +4 = -10 +4 = -6 . . . . . put -2 where x is, do the math

<h3>f(g(-2))</h3>

Now that we know g(-2) = -6, we know this expression is ...

f(-6) = 8 -10(-6) = 8 +60 = 68 . . . . . substitute for x in 8-10x

Then the value we're looking for is ...

(f∘g)(-2) = 68

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1 year ago

What is the equation in standard form or the line that passes through the point ( 4,-8 ) and has a slope of 1/4?

ehidna [41]

The equation in y=mx+b form is 1/4x-9.

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3 years ago

Factor the following polynomial completely.<br> -x^2y^2 + x^4 + 9y^2 - 9x^2

castortr0y [4]

See attached picture for answer:

3 0

3 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago