Answer:
Multiple choice means you get the more than one option and one of those options are correct while the rest are incorrect Multiple response means that you have to add more then one response to answer the question
The answer is 56! How you do this, is you take 80, and you multiply it by 7. Then you divide that answer by 10. Then you have your answer! I’m really bad at math but I do know how to do that!
Answer:
(x, y) = (-2, 7), (0, -1), (3, -13), (-1, 3)
Step-by-step explanation:
To fill in the y-values, you need to put the x-value in the equation and evaluate.
<u>for x=0</u>
y = -4(0) -1 = -1
<u>for x=-1</u>
y = -4(-1) -1 = 4 -1 = 3
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To fill in the x-values, we can solve for x and then do as we did above.
y = -4x -1
y +1 = -4x . . . . add 1
-(y +1)/4 = x . . . divide by -4
<u>for y=7</u>
x = -(7 +1)/4 = -2
<u>for y=-13</u>
x = -(-13+1)/4 = -(-12/4) = 3
__
Then the table is ...
Answer:
(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010
(b)
(1 – p) = 0.010
(c)
E(x) = 25000 x 0.010
= 259.2
Explanation has given below.
Step-by-step explanation:
Solution:
(a) Probability that a triplet is decoded.
2 out of three
P = 0.94, n = 3
m= no of correct bits
m bit (3, 0.94)
At p(m≤1) = B (1; 3, 0.94)
= 0.010
(b) Using your answer to part (a),
(1 – p) = 0.010
Error for 1 bit transmission error.
(c) How does your answer to part (a) change if each bit is repeated five times (instead of three?
P( m ≤ 2 )
L = Bit (5, 0.94)
= B (2; 5, 0.94)
= 0.002
(d) Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?
Given:
h = 25000
Bits are switched during transmission between two computers = 6% = 0.06
m = Bit (25000, 0.06)
E(m) = np
= 25000 x 0.06
= 1500
m = Bit (25000, 0.01)
E(m) = 25000 x 0.010
= 259.2
m is less than or equal to 4
