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Marysya12 [62]
3 years ago
5

A landscaper buys 1 gallon of plant fertilizer. He uses 1/5 of the fertilizer, and then divides the rest into 3 smaller bottles.

How much does he put in each bottle?
Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

4/15 gallon per bottle

Step-by-step explanation:

First, we find the remaining fraction of fertilizer after using 1/5. Using our fraction calculator, we see:

1 - 1/5 = 4/5

To find the amount of fertilizer per bottle, we then divide 4/5 by 3 and we get:

4/15 gallon per bottle

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The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m
larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words=\frac{13!}{4\times 2!\times 3!}=64,864,800

When M's are together . considering 2 M's as one

therefore there are \frac{12!}{3\times 2!\times 3!}=9,979,200

No of ways=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600

(b)No of ways such that M's are separated by at least 2 letters

at least  2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

=45738000

7 0
3 years ago
3. Solve the equation c2 = 80.
guapka [62]
C=40 bahshshahajehsh
4 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Please help me! Please!
user100 [1]

Answer:

C) -3 is the answer

6 0
3 years ago
Solve by completing the square.
enot [183]

Answer:

x^2 -8x -5 = -3

x^2 -8x -2 = 0

We complete the square by:

1) Moving the "non X" term to the right:

x^2 -8x  = 2

2) Dividing the equation by the coefficient of X²

The coefficient of x is 1 so we don't do anything

3) Now here's the "completing the square" stage in which we:

      • take the coefficient of X

that is -8

     • divide it by 2

-8 ÷ 2 = -4

     • square that number

-4*-4 = 16

     • then add it to both sides of the  equation.

x^2 -8x +16 = 2 +16

That becomes

(x -4)^2 = 18

we take the square root of both sides:

(x -4) = sqr root (18)

x1 = sqr root (18) +4

AND

(x+4) = sqr root (18) -4

x1 =  sqr root (18) +4 = 4.2426406871  + 4 = 8.2426406871

x2 = sqr root (18) -4 =  = 4.2426406871  - 4 = .2426406871

       

Step-by-step explanation:

8 0
3 years ago
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