The area of the shaded sector is one-fourth of the area of the whole circle so:

area of shaded region

The area of the shaded region is 9pi units^2
First, let's work with the denominator alone:
4⁻⁴ = 1 / 4⁴ = 1/256 .
The original problem is the reciprocal of that = 256.
Answer:
f(2) = 11
Step-by-step explanation:
f(x) = 3x+5
f(2) = 3(2)+5
f(2) = 6+5
f(2) = 11
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