Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
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8 percent (C)
To find 1% you divide 4.50 by 100, which is 0.045.
Then you have to find what is added on.
4.86-4.50 is .36
Now you divide .36 by 0.045. An easier way to do this is 360 divided by 45. This equals 8.
Hope this helped
Answer:
6 times 10^3
Step-by-step explanation:
You multiply 3 and 2 together and 10^7 and 10^-4 together. 3x2 is equal to 6 and 10^7 times 10^-4 is the same as 10^7-4 which is equal to 10^3. Therefore, the answer is 6 times 10^3.
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Answer:
Step-by-step explanation:
<u>Total number of integers from 300 through 780, inclusive:</u>
<u>Number of integers with at least one of digit 1:</u>
- Hundreds - 0,
- Tens - 5*10 = 50 (31th, 41th, 51th, 61th, 71th)
- Units - 4*9 + 7 = 43 (300 till 699 and 700 till 780)
- So in total 50 + 43 = 93
<u>The probability is:</u>
- P = favorable outcomes/total outcomes = 93/481
6 because 45 divides by 3 equals 15 and fifteen minus 9 equals 6, if you plug 6 into the equation it makes sense