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3 years ago

Explain how solving -7y > 161 is different from solving 7y > -161.

Mathematics

1 answer:

belka [17]3 years ago

8 0

Answer:

what the person above me said is correct :)

Step-by-step explanation:

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What is the value of this expression when a=3 and b=-1?

lesya692 [45]

Answer:

1/4

Step-by-step explanation:

$(\dfrac{3(3)^{-2}(-1)^6}{2(3)^{-1}(-1)^5})^2=$

$(\dfrac{\frac{1}{3}}{-\frac{2}{3}})^2=$

$(-\dfrac{1}{2})^2=$

$\frac{1}{4}$

Hope this helps!

5 0

3 years ago

Which function represents a translation of the graph of v=x^2

KatRina [158]

Answer:

Step-by-step explanation:

That would be y = (x +10)^2.

8 0

3 years ago

A square has a side length of 36 feet the square is dilated by a scale factor of 2/3 do you create a new square what is the side

Ronch [10]

you would multiply 36*2/3 and get 24 which would be the new side length

6 0

4 years ago

‼️⚠️⚠️‼️ HELP PLEASE WILL GIVE POINTS

kipiarov [429]

Answer:

m∠ABC=42°

Step-by-step explanation:

m∠ABD=70°

⇒m∠ABD=m∠ABC+m∠CBD

⇒70°=(3x+33°)+(5x+13°)

70°=8x+46°

70°-46°=8x

24°=8x⇒x=3°

x=3°

Then,

m∠ABC=3x+33°

put x=3°, we get

m∠ABC=3×3°+33°=9°+33°

m∠ABC=42°

3 0

3 years ago

The radius of a right circular cylinder is given by √(t+6) and its height is 1/6√t , where t is time in seconds and the dimensio

denis23 [38]

Answer:

The rate change of volume of the cylinder is $\frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t})$ cubic inch per second.

Step-by-step explanation:

Given that the radius of right circular cylinder is $\sqrt{(t+6)}$ and its height is $\frac16 \sqrt t$ where t is time in second and the dimension are inches.

$\therefore r = \sqrt{(t+6)}$

The base area of the cylinder is A= $\pi r^2$

$=\pi (\sqrt{t+6})^2$

$= \pi (t+6)$

$\therefore A= \pi(t+6)$

Differentiating with respect to t

$\frac{dA}{dt}=\pi$

$\therefore h=\frac16\sqrt t$

Differentiating with respect to t

$\frac{dh}{dt}=\frac16 \times \frac12(t)^{\frac12-1}$

$\Rightarrow \frac{dh}{dt}=\frac1{12} (t)^{-\frac12}$

The volume of cylinder is V= Ah

∴V= Ah

Differentiating with respect to t

$\frac{dV}{dt}=A\frac{dh}{dt}+h\frac{dA}{dt}$

$=\pi (t+6). \frac1{12}t^{-\frac12} +\frac16\sqrt t . \pi$

$=\pi. \frac1{12}.t^{\frac12}+\pi . 6.\frac1{12} t^{-\frac12} +\pi\frac16 \sqrt t$

$=\frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t})$

The rate change of volume of the cylinder is $\frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t})$ cubic inch per second.

5 0

3 years ago