See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer : 96
x – y = 16 --------> equation 1
1/8 x + 1/2 y = 52
x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation
1/8 x + 1/2 ( -16 + x ) = 52
1/8x - 8 + 1/2 x = 52
1/8x + 1/2x - 8 = 52
Take common denominator to combine fractions
1/8x + 4/8x -8 = 52
5/8x - 8 = 52
Add 8 on both sides
5/8x = 60
Multiply both sides by 8/5
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
-5y + 8x
Step-by-step explanation:
Okay, we know that the expenses for the day is 210.
Knowing this, and the price of the taco, we write the inequality:
3.25t > 210
t = number of tacos
Now divide both sides by 3.25:
t > 64.62 (rounded)
Because a taco stand can't sell a fraction of a taco, we know that the taco stand has to sell more than 65 tacos for a profit.
a=8+2=10; b=4•5=20; c=6-2=4
