Answer:
the height of the flagpole is 5 meters
Step-by-step explanation:
The computation of the height of the flagpole is given below
Given that
the length of the rope is 13 meters
And, the ground would be 12 meters
Based on the above information, the height of the flagpole is
= √13^2 - √12^2
= √169 - √144
= √25
= 5 meters
hence the height of the flagpole is 5 meters
Answer:
x=-2,2
Step-by-step explanation:
Since this is a quadratic equation, -2 or 2 could be the possible answer
Steps
$3x^2=12$
$\mathrm{Divide\:both\:sides\:by\:}3$
$\frac{3x^2}{3}=\frac{12}{3}$
$\mathrm{Simplify}$
$x^2=4$
$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$
$x=\sqrt{4},\:x=-\sqrt{4}$
Show Steps
$\sqrt{4}=2$
Show Steps
$-\sqrt{4}=-2$
$x=2,\:x=-2$
Just comparing your (x, y) points to the values on the table, it looks like b) would be the quick answer. Since it states under the table to use average values within each range.
So for x=62 (the weight), we have y=122 (the iron count) which would be the average of the range between 115 and 129.
Similiarly, x=70 corresponds to y=146, which is the average of 139 and 153.
You could take the average values of your highest and lowest iron count ranges compare them to the max-min weight to get your slope. Looks like it would be (155-112)/(73-58)= 43/15= 2.8666 repeating. That would make sense with the slope in the equation listed in b) as well.
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Answer:
4/5
Step-by-step explanation:
14 is a multiple of 7 and 14
