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saw5 [17]
3 years ago
11

Please help!! I’ll mark brainliest!

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

Just from looking at the picture, I'm assuming that we're trying to find the terms that are like to the terms in the blue section.

1. 8c since both are in terms of c

2. 7t since both are in terms of t

3. 8r since both are in terms of r

4. -4n since both are in terms of n

5. xy since both are in terms of xy

6. 16 since both don't have any variables

7. 4sp since both are in terms of sp

Step-by-step explanation:

MrRa [10]3 years ago
7 0

Answer:

8r and -2r

xy and 6xy

8c and 19c

16 and 97

4sp and sp

7t and 13t

-4n and 10n  

Step-by-step explanation:

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There are 12 inches for every 1 foot. How many inches are equivalent to 4 feet?
Fantom [35]

Answer:

48 inches

Step-by-step explanation:

12 in=1

24 in = 2

36 in = 3

48 in = 4

Add 12 everytime

4 0
3 years ago
How would you round this to the nearest mile 244.1399784294165944?
KonstantinChe [14]
It would be rounded down to 244 as its only .1 so its closer to 244 than it is to 245
4 0
3 years ago
Read 2 more answers
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
2 years ago
Malik’s solution to the equation 2/5x-4y=10 , when x=60, is shown below.
zhenek [66]

Answer:

D. Malik substituted 60 for y instead of x.

Step-by-step explanation:

Look closely at the step by step process.

4 0
3 years ago
Read 2 more answers
3. Given Q = (-1,4) and P = (-2,-2), find QP.​
astra-53 [7]

Step-by-step explanation:

QP=P-Q

QP=(-2,-2)-(-1,4)

QP=(-1,-6)

5 0
3 years ago
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