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3 years ago

Please help!! I’ll mark brainliest!

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

Just from looking at the picture, I'm assuming that we're trying to find the terms that are like to the terms in the blue section.

1. 8c since both are in terms of c

2. 7t since both are in terms of t

3. 8r since both are in terms of r

4. -4n since both are in terms of n

5. xy since both are in terms of xy

6. 16 since both don't have any variables

7. 4sp since both are in terms of sp

Step-by-step explanation:

MrRa [10]3 years ago

7 0

Answer:

8r and -2r

xy and 6xy

8c and 19c

16 and 97

4sp and sp

7t and 13t

-4n and 10n

Step-by-step explanation:

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Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

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So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

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