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aniked [119]
3 years ago
15

| What is the median(middle) of the following: 1, 2, 2, 5, 7, 9, 12, 13

Mathematics
2 answers:
timofeeve [1]3 years ago
4 0
The answer would be five
mixer [17]3 years ago
4 0

Step-by-step explanation:

the answer is a,hope it helps

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Whats the equation 2+2 yo
anyanavicka [17]
Sheesh I think is 4 :)
4 0
3 years ago
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Find the sum or difference of the polynomials (x2−xy+y2) − (x2+xy+y2)
stepan [7]
The correct answer is-2xy if it’s subtract
6 0
3 years ago
What is the horizontal asymptote of the function f(x)= -2x/x+1
daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = -\frac{2}{1} = -2

8 0
3 years ago
Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

Therefore , the solutions to the related equation are 0,2,3 .

3 0
3 years ago
Please help meeeeee​
klasskru [66]

Answer:

Step-by-step explanation:

Y= 5/2x+5. :D

8 0
2 years ago
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