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2 years ago

4/2 (6time y) what shiuld be the answer

Mathematics

1 answer:

tino4ka555 [31]2 years ago

3 0

Answer:

12y i think

Step-by-step explanation:

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Reflected over the x-axis, then translated 6<br> units left

lapo4ka [179]

Take the original coordinate (x,y)
to reflect over x-axis change it to (x,-y)
*basically change the sign of y*
to translate 6 units left (x-6,y)
* basically subtract 6 from x
So your new point should be (x-6,-y)

7 0

3 years ago

The the intensity I of light (in lumens) in a certain lake at a depth of x feet is given by log(1/12) = -0.00235x. What is the i

ch4aika [34]

Answer:

11.45 lumens

Step-by-step explanation:

We are given that

$log(I/12)=-0.00235x$

Where x=Depth

I=Intensity of light

We have to find the intensity of the light at a depth of 20 feet.

Substitute the value of x

$log(I/12)=-0.00235\times 20$

$log(I/12)=-0.047$

$\frac{I}{12}=e^{-0.047}$

$I=12e^{-0.047}$

$I=11.45 Lumens$

Hence, the intensity of the light (in lumens) at a depth of 20 feet=11.45 lumens

4 0

3 years ago

Why does it make sense to use 660 and 60 to estimate the quotient

Alexxx [7]

What the qoutient sweetheart

5 0

3 years ago

What is the equation in slope-intercept from of the line that passes through the points (-4,47) and (2,-16

Harrizon [31]

Answer:

Step-by-step explanation:

<u><em>SLOPE FORMULA:</em></u>

y₂-y₁/x₂-x₁=rise/run

<u><em>SLOPE-INTERCEPT FORM:</em></u>

y=mx+b

m represents the slope.

b represents the y-intercept.

y₂=(-16)

y₁=47

x₂=2

y₁=(-4)

Solve.

$\displaystyle \mathsf{\frac{(-16)-47}{2-(-4)}=\frac{21}{6}=\frac{21}{2}=-\frac{21}{2} }}$

Furthermore, the y-intercept is 5.

y=-21/2x+5

The correct answer is y=-21/2x+5.

6 0

3 years ago

Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x

alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0

3 years ago