<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%20%20%5Cfrac%7Bv%7D%7B5%7D%20%20%3E%20%20-%201" id="TexFormula1" title=" - 3 +

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4 years ago

15

\frac{v}{5} > - 1" alt=" - 3 + \frac{v}{5} > - 1" align="absmiddle" class="latex-formula">

1 answer:

SVETLANKA909090 [29]4 years ago

3 0

-3+ v/5 > -1
V/5>2
V>10

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Step-by-step explanation:

No need for a calculator.

Assuming that the equation is in the form $y = ab^x$ , we can plug in points to get our equation. For ease, let's use (1,18) and (2,21). When plugging these points in, we get $18 = ab^1, 21 = ab^2$ . Now let's divide the equations to get rid of $a$ : $\frac{21 = ab^2}{18 = ab^1} = \frac{21}{18} = \frac{7}{6} = b$ . Now that we have $b$ , we can plug in the value we just calculated to solve for $a$ : $18 = a(\frac{7}{6} )^1$ , and solving for $a$ , we get $a = \frac{108}{7}$ .

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This equation in decimal form (rounded to the nearest thousandth) is $f(x) = 15.429(1.167)^x$ .

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