S=d/t ⇒d=s*t
s=speed
d=distance
t=time
The first train :
d=x
x=70 miles/h*t ⇒ x=70t (1)
The second train
d=360 miles - x
360 miles - x=80 miles/h*t ⇒360-x=80t ⇒ x=360-80t (2)
therefore, with the equations (1) and (2) we have a systeme of equations:
x=70t
x=360-80t
we can solve this system of equations by equalization method.
70t=360-80t
70t+80t=360
150t=360
t=360/150=2.4 (≈2 hour 24 minutes)
Answer: the first train meet with the second train in 2 hour 24 minutes.
Answer:
A. 48
Step-by-step explanation:
If you go on my profile you will see a similar problem that I already answered today.
Lets start by using a formula (don't remember the name)
(y-y1)=M(x-x1)
M is slope and y is first y value and y1 is second y value same applies to X.
Substitute in the values.
(5-q) = 10(-6-(-7))
5-q = 10*(1)
5-q = 10
-q = 5
q = -5
Check:
Substitute in the value of "q" and use the formula to find slope:
(y1-y)/(x1-x)
Substitute
(-5-5)/(-7-(-6))
-10/-1
10
Your Answer:
The value of "q" is -5
<span>THE GIVEN QUESTION;
7x -3(4x-8) < 6x +12 - 9x
THE GIVEN INTERVAL OF X IS FROM [4,8] SO THE VALUE OF X ={4,5,6,7,8}
THE GIVEN QUESTION CAN BE EVALUATED TO
7x - 12x+ 24 < 12 - 3x
-5x + 24 < 12 - 3x //USING BODMAS RULE
NOW SUBSTITUTING THE VALUE OF X:
1) X=4 SOL: 4<0
2) X=5 SOL: -1<-3
3) X=6 SOL: -6<-6
4) X=7 SOL: -11<-9
5) X=8 SOL: -16<-12
HENCE THE VALUE OF X=7,8 SATISFY THE GIVEN INEQUALITY</span>
