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iogann1982 [59]
3 years ago
10

100 points! Please help! Will mark brainliest! Random answers will be reported :)

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Step-by-step explanation: (3,0)

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Please help meeeeeeeeeeeeee
romanna [79]

Answer:

Umm, I think you need to add your attachment.

Step-by-step explanation:

7 0
3 years ago
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Which graph best represents the solution to the system of equations shown below?
goldfiish [28.3K]

First find the x and y values because where the lines will intersect, they share the point of the intersection so they will share the x and y coordinates.

Rearrange equations

4x + y = 19

- 2x + y = 1

To cancel y, we must do equation 1 minus equation 2. Similarly:

4x -  - 2x = 4x + 2x = 6x

19 - 1 = 18

6x = 18

x = 18 \div 6 = 3

So the x coordinate is 3.

The y coordinate can be found with substitution of x into one of the equations:

y = 2x + 1 = 2(3) + 1 = 7

So where the two lines intersect is at the point (3, 7), which is the solution to the equations.

4 0
3 years ago
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3.) Find the measure of the missing angle X:<br> Xº<br> 120°<br> 70°
Otrada [13]

Answer:

x=50

Step-by-step explanation:

Let's look at the red angle. if a flat line makes the angle 180, and the outer angle is 120, subtract 120 from 180. This will give you 60. Now every angle of a triangle added together will give you the sum of 180. So you already have 60 and 70, which make 130 all together. Subract 130 from 180 - (180-130) - and you'll get the result of 50.

5 0
3 years ago
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Find the length of the curve x=e^t e^{-t},\;\;y=5-2t,\;\;0 \le t \le 3.
Oksana_A [137]
\begin{cases}x(t)=e^t+e^{-t}\\y(t)=5-2t\end{cases}\implies\begin{cases}x'(t)=e^t-e^{-t}\\y'(t)=-2\end{cases}

The length of the curve is given by the integral

\displaystyle\int_0^3\sqrt{(e^t-e^{-t})^2+(-2)^2}\,\mathrm dt

Expand and rewrite the integrand:

(e^t-e^{-t})^2+(-2)^2=e^{2t}+2+e^{-2t}
=e^{-2t}(e^{4t}+2e^{2t}+1)
=e^{-2t}(e^{2t}+1)^2
\implies\sqrt{(e^t-e^{-t})^2+(-2)^2}=\dfrac{e^{2t}+1}{e^t}

Now the integral is

\displaystyle\int_0^3\dfrac{e^{2t}+1}{e^t}\,\mathrm dt=\int_0^3(e^t+e^{-t})\,\mathrm dt
=2\displaystyle\int_0^3\cosh t\,\mathrm dt
=2\sinh t\bigg|_{t=0}^{t=3}
=2\sinh 3
7 0
3 years ago
Suppose you drop the ball from a window 20 ft above the ground. Predict how high the ball will bounce.
navik [9.2K]
Tennis balls bounce about 53% and a regular typical ball is around 60% of their dropped highs. So maybe 12ft idk
6 0
3 years ago
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