6/24 and 5/16 are the two friends who would have drank 1/4 of the juice.
Answer:
The inverse relation G^(-1) is not a function. Why not? Because the y value y = 3 is paired up with more than one x value (x = 5, x = 2). The inverse relation G^(-1) is the set shown below
{(3,5), (3,2), (4,6)}
All I've done is swap the (x,y) values for each ordered pair to form the inverse relation. As you can see, x = 3 leads to multiple y value outputs which is why this relation is not a function. So in short, the answer is choice C. To have the inverse relation be a function, each value in the original domain must map to exactly one value in the range only. However that doesn't happen as the domain values map to an overlapping y value (y = 3).
1) Base
2) Exponent
3) Metric system
Answer:
x ≠ 4 or -2
Step-by-step explanation:
the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.
3x^2 - 6x - 24 ≠ 0
3(x^2 - 2x - 8) ≠ 0 (factor out a 3)
3(x - 4)(x + 2) ≠ 0 (factor equation)
x ≠ 4, x ≠ -2 (use zero product property to find zeros)
