There is a line who slope is 3 and who’s Y intercept is -10. Right it’s equation in slope intercept form

Find a parametric representation for the surface. the part of the plane z = x + 3 that lies inside the cylinder x2 + y2 = 9. (en

Evgesh-ka [11]

The cylinder is a clue to use cylindrical coordinates. Taking $x=3\cos\theta$ and $y=3\sin\theta$ , we then are forced to use $z=3\cos\theta+3$ . So the parameterization of the intersection of the plane and cylinder is

$\mathbf s(\theta)=(3\cos\theta,3\sin\theta,3\cos\theta+3)$

To get the surface, we can introduce a second parameter $r$ that "contracts" the elliptical intersection to a point. The simplest way to do this is to use

$\mathbf s(r,\theta)=(3r\cos\theta,3r\sin\theta,3r\cos\theta+3)$

with $0\le r\le1$ and $0\le\theta\le2\pi$ .

7 0

2 years ago

Work out 5(-2) x 327 Give your answer as a decimal.

GarryVolchara [31]

Answer: 0.12

5^-2=0.04
the cube root of 27=3
0.04x3=0.12

6 0

2 years ago

A frustum is formed when a plane parallel to a cone’s base cuts off the upper portion as shown. Which expression represents the

Bezzdna [24]

Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.

The volume of a cone is:

$V = \dfrac{1}{3} \pi r^2 h$

Total volume:

$V_t = \dfrac{1}{3} \times \pi \times 7.5^2 \times 19$

Volume of upper cone:

$V_u = \dfrac{1}{3} \times \pi \times 3.5^2 \times 8$

Volume of frustum:

$V_f = \dfrac{1}{3}\pi(7.5^2)(19) - \dfrac{1}{3}\pi(3.5^2)(8)$

3 0

3 years ago

Read 2 more answers

Two kinds of crated cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200

BlackZzzverrR [31]

Answer:

The correct answer is option b)

50a+10b<1000; 200a+360b < 7200; a> 0; b>0

Step-by-step explanation:

We are given that Two kind of crated cargo namely A and B to be shipped by truck.

Cargo A:

Volume of each crate of cargo A = 50 cubic ft

Weight of each crate of cargo A = 200 pounds

Let number of crates of cargo A to be shipped = a

Total volume of 'a' crates of cargo A = 50a cubic ft

Total weight of 'a' crates of cargo A = 200a pounds

Cargo B:

Volume of each crate of cargo B = 10 cubic ft

Weight of each crate of cargo B = 360 pounds

Let number of crates of cargo B to be shipped = b

Total volume of 'b' crates of cargo B = 10b cubic ft

Total weight of 'b' crates of cargo B = 360b

Total volume allowed in the truck is 1000 cubic ft

Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

$50a+10b$ ....... (1)

Total weight allowed (load limit) in the truck is 7200 pounds

Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

$200a+360b$ ....... (1)

And number of crates of cargo A and B are always a positive number.

So, a > 0 and b > 0.

So, the correct answer is option b.

b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0

3 0

3 years ago

An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below

madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that $\mu = 79.7, \sigma = 8.4$