(g-h)(x) = 2x+1 -(<span>x-2)
</span>(g-h)(x) = 2x+1 - x + 2
(g-h)(x) = x + 3
5x-16 = 4(x-8)-3x
first expand what is in parenthesis
4(x-8) = 4x-32
so now you have 5x-16 = 4x-32-3x
subtract 3x from 4x on the right side of equation 4x-3x = x
5x-16 = x -32
subtract 1x from each side to get
4x-16 = -32
add 16 to both sides to get 4x=-16
x = -16/4 = -4
x=-4
Answer:
(x+10)+(×+50)=180(exterior co- interior angel
2x+60=180
2×=180-60
×=120/2
×=60
(6x+3)=(7x-12)(corresponding angle )
3+12=7×-6×
x=15
4x-2=3x-19(vertically opposite angle)
4x-3×=-19+2
x=-17
The answer is: x² – 6x + 9 = 0 .
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Explanation:
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Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 .
<span>
Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
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Rewrite: (x – 3)² = 0 ; →
as: x² – 6x + 9 = 0 ; which is our answer.
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→ x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ;
→ in which:
a = 1 (implied coefficient, since anything multiplied by "1" is that same value);
b = -6;
c = 9
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