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Alik [6]
3 years ago
12

I’m having a hard time finding the answer, any help is appreciated (:

Mathematics
1 answer:
kogti [31]3 years ago
3 0

Answer:

True.

Step-by-step explanation:

It fails the vertical line test. The vertical line test checks to see if any inputs (x values) have more than one output. In this case, they do.

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You make $30 in 2 1/2 hours of work how much do you make in 1 hour
Gnesinka [82]

Answer:14.6341463415

Step-by-step explanation:

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3 years ago
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A random sample of 36 students at a community college showed an average age of 25 years. assume the ages of all students at the
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<span>24.301 to 25.699 hopw this helps

</span>
8 0
3 years ago
If 9 exercise books cost<br>$540.00. how much will<br>14 of such cost?​
Marina CMI [18]

Answer:

$840 dollars

Step-by-step explanation:

Divide 540 by 9 to get the cost of 1 book then multiply it by 14

8 0
2 years ago
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(06.04 MC)
Andru [333]

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

◉ \large\bm{ -4}

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

Before performing any calculation it's good to recall a few properties of integrals:

\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx +  \int_{a}^bmdx}

\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a  f(x)dx= \int^c _a f(x)dx+  \int^{b} _c  f(x)dx }

So we apply the first property in the first expression given by the question:

\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}

And we solve the second integral:

\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx  = 2 \int ^3_{-2} f(x)dx +   2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }

Then we take the last equation and we subtract 10 from both sides:

\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  = 8}

And we divide both sides by 2:

\small\longrightarrow \sf{\dfrac{2  {  \int}^{3} _{2}  }{2}  =  \dfrac{8}{2} }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}

Then we apply the second property to this integral:

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}

Then we use the other equality in the question and we get:

\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  =  2 \int ^3_{-2} f(x)dx  = 8 +  2 \int ^3_{-2} f(x)dx  = 4}

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}

We substract 8 from both sides:

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}

• \small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}

7 0
2 years ago
Find the circumference of the circle.
DaniilM [7]

Use this formula: C=2πr. Divide 14/2 to get the radius. Substitute the radius into the formula.

The answer is 14pi units.


<u>Please mark this answer as the Brainliest if it helped! Thank you.</u>

5 0
3 years ago
Read 2 more answers
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