Question

Write the standard form of the equation of the circle described below.

Answer 1

Equation of circle is $x^2+(y-2)^2=52$

Step-by-step explanation:

The standard form of the equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius of circle.

We need to find the radius of circle r by using distance formula:

$[tex]r=d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\\r=d=\sqrt{(4-0)^2+(-4-2)^2}\\r=d=\sqrt{(4)^2+(-6)^2}\\r=d=\sqrt{16+36}\\r=d=\sqrt{52}$

r=√52

and r^2= 52

Putting values of r^2=52 and value of center (h,k)=(0,2)

the equation of Circle is:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-2)^2=52\\x^2+(y-2)^2=52$

Keywords: Equation of circle

Learn more about Equation of circle at:

• brainly.com/question/1952668
• brainly.com/question/2115496
• brainly.com/question/3333996

#learnwithBrainly