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3 years ago

-3 - square root of-12 divided by 24

Mathematics

1 answer:

posledela3 years ago

7 0

Answer:

Undefined

Step-by-step explanation:

if its -3-√-12 ÷24 it would be undefined. Unless you wrote the question wrong I will answer again.

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In a college math class of 50 students, 23 are boys and 27 are girls. On the final exam, 15 boys and 14 girls made an A. What is

GenaCL600 [577]

boy or an A student is

29 made an A + 8 boys who did not make an A

37 who made an A and/or who is a boy

37/50

3 0

3 years ago

Hi 6 6 h h 13 13 Find the missing height. h = h=h, equals units The parallelogram shown below has an area of 72 7272 units 2 2 s

Yakvenalex [24]

Answer:

Height=12 Units

Step-by-step explanation:

Given a parallelogram with base b, and a perpendicular height, h. The area of the parallelogram is derived using the formula:

Area of a parallelogram=Base X Perpendicular Height

Given an area of 72 Units Squared.

Since I am not certain of the length of the base given:

If b=6

Area=bh

72=6h

Dividing both sides by 6

h=12 Units.

Height=12 Units

You can use the given formula to solve for the height,h of the parallelogram given any base b.

3 0

3 years ago

Find the equation of the line shown

yuradex [85]

Answer:

$y = 2x - 1$

Step-by-step explanation:

The line shown is a straight line its equation is of the form.

$y = mx + c$

Where m is the slope and c is the y-intercept.

From the graph, the slope is

$m = \frac{rise}{run}$

$m = \frac{2}{1} = 2$

The y-intercept from the graph is where the line intersects the y-axis, so c=-1

We substitute the values to get:

$y = 2x - 1$

5 0

3 years ago

In the figure, the perimeter of hexagon ABCDEF is approximately ___

blsea [12.9K]

Let
$F(-10,0) A(10,10) B(20,10) C(30,0) D(20,-10) E(10,-10)$
we know that
$FA=FE \\ AB=ED \\ BC=CD$

step 1
find distance FA
$dFA= \sqrt{ (y2-y1)^{2} +(x2-x1)^{2} } \\ dFA= \sqrt{ (10-0)^{2} +(10+10)^{2}$

$dFA= \sqrt{500} \\ dFA=22.36 units$

step 2
find distance AB
$dAB=20-10 \\ dAB=10 units$

step 3
find the distance BC
$dBC= \sqrt{ (y2-y1)^{2} +(x2-x1)^{2} }$
$dBC= \sqrt{ (0-10)^{2} +(30-20)^{2} }$
$dBC= \sqrt{200}$
$dBC=14.14 units$

step 4
find the perimeter
the perimeter is equal to
$P=2*[FA+AB+BC] \\ P=2*[22.36+10+14.14] \\ P=93 units$

step 5
find the area
the area is equal to
area triangle AFE+area rectangle ABDE+area triangle BDC

step 6
find the area of triangle AFE
$A1=20*20/2 \\ A1=200 units^{2}$

step 7
find the area of the rectangle ABDE
$A2=10*20 \\ A2=200 units^{2}$

step 8
find the area of the triangle BDC
$A3=20*10/2 \\ A3=150 units^{2}$
$Area Total=200+200+150 \\ Area Total=550 units^{2}$

8 0

3 years ago

Read 2 more answers

I don’t know how to do this one I need help

vova2212 [387]

Solve for w by simplifying both sides of the equation by isolating the variable then combining like terms w= -3

5 0

3 years ago

-3 - square root of-12 divided by 24​

-3 - square root of-12 divided by 24