Answer: sulfur pentafluoride
Explanation:
The rules for naming of binary molecular compound :
In the given formula, the lower group number element is written first in the name and keep its element name and the higher group number is written second.
First element i.e. sulphur in the formula is named first and keep its element name.
1) Gets a prefix if there is a subscript on it such as mono for 1, di for 2, tri for 3 and so on.
Second element i.e. fluorine is named second.
1) Use the root of the element name, if it is an anion then use suffix (-ide).
2) Always use a prefix on the second element such as mono for 1, di for 2, tri for 3 and so on.
Therefore, the chemical name of compound 
is sulfur pentafluoride
Water is a compound. A compound is made up of two or more elements. In the case of water, or H2O, there are 2 hydrogen atoms present and 1 oxygen atom. I hope this helps you on your assignment. Good luck!
D. There must be oxygen added. 2 of them don't even have oxygen anywhere in the formula, and the 3rd loses oxygen, which is reduction.
Answers and explanation:
To answer these questions you use a periodic table.
A is In because it has 49 protons and In is element number 49.
B is 27 because Co is element number 27.
C is 73 because Ta is element number 73.
D is 49 because the number of electrons in an atoms is always equal to the number of protons.
E is 56 because the atomic number of Ba is 56.
F is 54 because 56 - 54 = 2. The charge is equal to the number of protons minus the number of electrons.
G is 66. The number of neutrons is equal to the atomic mass minus the number of protons. 115 - 49 = 66.
H is 108 because 181 - 73 = 108.
I is 32. The atomic mass of an element is equal to the amount of protons plus the amount of neutrons. So 16 + 16 = 32.
Answer:
1.1 M
Explanation:
The dissociation of 
is as follows:
Given Value for 
The equation for the reaction for the formation of complex ion 
is :
The value of 
If we combine both equation and find the overall equilibrium constant will be:
<u> </u>
If ![[NH_3]](https://tex.z-dn.net/?f=%5BNH_3%5D)
= x M
The solubility of in the 
solution will be:
Constructing an ICE Table; we have :
Initial (M) x 0 0
Change (M) -2 (0.0518) + 0.0518 + 0.0518
Equilibrium (M) x - 0.1156 0.0518 0.0518
Equilibrium constant;
(K) = ![\frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAg%28NH_3%29_2%5E%2B%5D%5BCl%5E-%5D%7D%7B%5BNH_3%5D%5E2%7D)
x = [NH₃] = 1.089 M
[NH₃] ≅ 1.1 M
