The molecule is the representative particle of molecular compounds. It is also the representative particle of diatomic elements.
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Answer: Please find answer in explanation column
Explanation:
During radioactive decay, the __unstable ________ isotope decays into a _stable ___________ isotope that has a different ____proton _______________ number
Or
During radioactive decay, the _ unstable parent nuclide ________ isotope decays into a _stable daughter nuclide ___________ isotope that has a different ____proton _______________ number.
There are 3 types of radioactive decay;alpha, beta and gamma, Of which the above clearly explains the beta decay. In beta decay, the unstable isotope having excess neutrons will undergo a beta decay emitting a beta particle.( ⁰₋₁e) causing the nucleus to loose a neutron but gain a proton.
Some heavy unstable isotopes which undergo radioactive (beta decay ) to become stable isotopes are phosphorus-32, strontium-90, iodine-131
Using Strontium 90 as an example , we have
⁹⁰₃₈St ----->⁹⁰₃₉Y + ⁰₋₁e
Strontium an unstable isotope undergoes a beta radioactive decay to form Yttrium.
Answer:
There are three possible chemical equations for the combustion of sulfur:
- 2S (s) + O₂ (g) → 2SO (g)
- 2S (s) + 3O₂ (g) → 2SO₃ (g)
Explanation:
<em>Combustion</em> is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.
<em>Sulfur</em> iis a nonmetal, so the oxide formed is a nonmetal oxide.
The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.
The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).
Then you have three different equations for sulfur combustion:
<u>1) Oxidation number +2:</u>
Which when balanced is: 2S(g) + O₂(g) → 2SO(g)
<u>2) Oxitation number +4:</u>
That equation is already balanced.
<u>3) Oxidation number +6:</u>
Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)
