Question

Write the equation of a circle with a center at (2, -9) and a radius of 7 Helpppp

Answer 1

Answer:

$x^2+y^2+14y+36=0$

Step-by-step explanation:

Given that,

Center = (2,-9)

Radius of the circle, r = 7

We need to find the equation of a circle with a center at  (2, -9) and a radius of 7. It can be given by :

$(x-h)^2+(y-k)^2=r^2$

Put h = 2, k = -9 and r = 7 So,

$(x-2)^2+(y-(-9))^2=7^2\\\\x^2+4-4x+y^2+81+18y=49\\\\x^2+y^2+14y+85-49=0\\\\x^2+y^2+14y+36=0$

Hence, this is the required solution.