Write the equation of a circle with a center at
(2, -9) and a radius of 7
Helpppp
1 answer:
Answer:
![x^2+y^2+14y+36=0](https://tex.z-dn.net/?f=x%5E2%2By%5E2%2B14y%2B36%3D0)
Step-by-step explanation:
Given that,
Center = (2,-9)
Radius of the circle, r = 7
We need to find the equation of a circle with a center at (2, -9) and a radius of 7. It can be given by :
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
Put h = 2, k = -9 and r = 7 So,
![(x-2)^2+(y-(-9))^2=7^2\\\\x^2+4-4x+y^2+81+18y=49\\\\x^2+y^2+14y+85-49=0\\\\x^2+y^2+14y+36=0](https://tex.z-dn.net/?f=%28x-2%29%5E2%2B%28y-%28-9%29%29%5E2%3D7%5E2%5C%5C%5C%5Cx%5E2%2B4-4x%2By%5E2%2B81%2B18y%3D49%5C%5C%5C%5Cx%5E2%2By%5E2%2B14y%2B85-49%3D0%5C%5C%5C%5Cx%5E2%2By%5E2%2B14y%2B36%3D0)
Hence, this is the required solution.
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