Answer:
(-4,-4)
Step-by-step explanation:
Since this is centered at (0,0), we have to multiply the x and the y coordinates by the scale factor.
-8 × 1/2 = -4
Answer:
<h3>No solutions: 5 - 4 + 7x + 1 = 7x + 1</h3><h3>One solution: 5 - 4 + 7x + 1 = 2x + 1</h3><h3>Infinitely many solutions: 5 - 4 + 7x + 1 = 7x + 2</h3>
Step-by-step explanation:
left side: 5 - 4 + 7x + 1 = 1 + 7x + 1 = 7x + 2
<u>No solution</u> is when we have the same number of x-es and different sums of other numbers on both sides of equation. So we have to put 7 next to x and any numer except 2 at the second place.
So the right side could be 7x+1 or 7x+3 or 7x+125 and so on.
<u>One solution</u> is when we have different number of x-es on both sides of equation. The sums of other numbers could be any numbers.
So the right side could be ex.: 2x+1, x+2, 8x, 3x+(-18), and so on.
<u>Infinitely many solutions</u> is when we have the same number of x-es and the same sums of other numbers on both sides of equation. So we have to put 7 next to x and numer 2 at the second place.
So the right side has to be 7x + 2
Answer:
x = 2.75
Step-by-step explanation:
3^2 +4^2 =c^2
9+16=25
5^2 =25
5-2.25= 2.75
Your answer is going to be 4/7
![\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertical%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Ck%2Bp%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7By%3Dk-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,
vertex is at (0,0)
the focus point is "p" or 5 units down from there, namely at (0, -5)
the directrix is "p" units on the opposite direction, up, namely at y = 5
the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.
