Simplify this expression √108

Mathematics

1 answer:

vredina [299]3 years ago

4 0

Answer:

Step-by-step explanation:

The square root of 108 is 54 because 108 divided by 2 = 54

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What is the answer for the equation 4|x+1/3|=20 ?

Llana [10]

I hope this helps you...

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3 years ago

Read 2 more answers

Help me idk how to do this

ElenaW [278]

To do this, you have to plug each x value into the rule.

1.y = 15 - 3×2
y = 15 - 6
y = 9

So the first y value would be 9.

2.y = 15 - 3×3
y = 15 - 9
y = 6

3. y = 15 - 3×4
y = 15-12
y = 3

4. y = 15 - 3×5
y = 15-15
y = 0

Hope this helps!

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4 years ago

If f is a function and x is an element in its domain, which statement is true about the graph of f?

Arada [10]

An appropriate choice among these is
The graph of f is the graph of the equation y = f(x).

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Horizontal and vertical axes of the Cartesian plane are conventionally labeled and referred to as "x" and "y", respectively. When we talk about the graph of f(x) in that context, we usually mean the graph of y=f(x). However, this convention may not be followed in all cases. There may be no "y" label on the graph at all, or the horizontal axis may be labeled something other than "x".

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3 years ago

Two circles, one of radius 5 inches, the other of radius 2 inches, are tangent at point P. Two bugs start crawling at the same t

lawyer [7]

Answer:

40 minutes

Step-by-step explanation:

The circumference of the larger circle is ...

C = 2πr = 2π(5 in) = 10π in

The bug navigates the circumference at 3π in/min, so will take

time = distance/speed = (10π in)/(3π in/min) = 10/3 min

to travel once around.

The circumference of the smaller circle is ...

C = 2πr = 2π(2 in) = 4π in

The bug navigates this circumference at 2.5π in/min, so will take

(4π in)/(2.5π in/min) = 8/5 min

to travel once around.

The bugs will meet at a time that is the least common multiple of these times. Both can be expressed in 15ths of a minute as ...

{50/15, 24/15}

Then the LCM of these will be ...

(1/15)LCM(50, 24) = (1/15)(50×24)/GCD(50, 24) = 1200/30 = 40

It will be 40 minutes before the bugs next meet at point P.

___

A graphing calculator can make use of the mod function to show when the bugs meet at point P (total is displacement of the two bugs from P is zero). It shows the meeting occurs after 40 minutes.