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GREYUIT [131]
3 years ago
9

What is -6n - 2n =16

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
-6n -2n = 16
-8n = 16
n = 16/-8
n = -2

Answer: n = -2
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Solving Equations with the variable on each side
Maslowich
Multiply both sides by 6
(b-4)/6*6= b-4
b/2*6= 3b

Rewrite the equation
b-4= 3b

Subtract b from both sides
-4=2b

Divide both sides by 2
-2=b

Final answer: b=-2
5 0
3 years ago
I don’t understand, help please ?!
GREYUIT [131]
I think you multiply or add
5 0
3 years ago
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What's the next number? 5, 3, 2, 6, 7, 9, 1, 15, 4, 2, 3, 3, 9, 5, 1, (?)​
tino4ka555 [31]

Answer:

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2 years ago
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Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
When evaluating (6.28x10^12)/(3.14x10^4) what will be the exponent of 10 in the quotient?
alexdok [17]
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hope this helps!
4 0
3 years ago
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