1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergejj [24]
3 years ago
11

Anyone know this? algebra 1 is so hard LOL

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

Y= 2x+3

Step-by-step explanation:

The slope of two parallel lines are always the same.

You might be interested in
Identify A, B, and C in the equation x - 3y + 4 = 0.
daser333 [38]

Option D:

A = 1, B = –3 and C = 4.

Solution:

Given equation is x – 3y + 4 =0.

General equation of a line format:

<em>Ax + By + C = 0</em>

<u>To identify A, B and C in the given equation:</u>

x – 3y + 4 =0 is a equation of a line which is in the form of Ax + By + C = 0.

That is,

The coefficient of x is A ⇒ A = 1

The coefficient of y is B ⇒ B = –3

The constant term is C ⇒ C = 4

A = 1, B = –3 and C = 4.

Hence Option D is the correct answer.

5 0
3 years ago
What is the length of a rectangle whose perimeter is 38 cm and its weight is 9 cm​
Tanzania [10]

Answer:

The length of the rectangle is 29 cm.

Step-by-step explanation:

38 - 9 = 29

8 0
3 years ago
DOES SOMEONE UNDERSTAND???
Vlad1618 [11]

Answer:

g(x) = 1: 0

g(-2) = -3

Step-by-step explanation:

Just by looking at the graph, at the origin, <em>x</em><em> </em>is 0 and g(x)<em> </em>is 1. Now, look at where <em>x</em><em> </em>is -2. Below that, you see where g(-2) is because -2 REPLACED <em>x</em><em>.</em>

I am joyous to assist you anytime.

**Subscribe to my You-Tube channel [USERNAME: MATHEMATICS WIZARD] for more assistance whenever you need it.

4 0
3 years ago
sweet t has 2 orange picks for every 5 green. I f there are 21 picks in all, how many picks are orange?
weeeeeb [17]
If there are 21 picks, 6 are orange
8 0
4 years ago
Read 2 more answers
Find the sum of the equation
stealth61 [152]

Answer:

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Step-by-step explanation:

1)  Rewrite {y}^{2}-2y+1y  in the form{a}^{2}-2ab+{b}^{2}, where a = y and b = 1.

\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}

3)  Factor {y}^{2}+6y-7.

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

(y-1)(y-7)

Outcome/Result: \frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}

4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

5)  Expand.

\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}

7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

5 0
2 years ago
Read 2 more answers
Other questions:
  • How do you convert .375 into a fraction and percent?
    5·1 answer
  • Liam wants to estimate the percentage of people who lease a car. He surveys 240 individuals and finds that 54 lease a car. Find
    6·1 answer
  • Describe the transformation using the values for slope (m) and the y-intercept b. Compare the graph to the parent y = x.
    8·1 answer
  • Match transformation of the function y = csc x with description of the resultant shift in the original cosecant graph. Tiles -1
    10·1 answer
  • NEED HELP WITH 2 and 3
    12·1 answer
  • The sum of two numbers is 51 and the difference is 15 . What are the numbers?
    11·1 answer
  • Brad paints a house in 5 days. When his brother Nick joins him, they can paint a house in 3 days. How long does it take Nick to
    13·1 answer
  • Solve for -6= b/18
    5·1 answer
  • What is the price of a $13 ticket with a 8% sales tax?
    10·2 answers
  • A student in a foreign language program learns 15 new words each week. Which graph best represents the relationship between x, t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!