Ask question

Ask question

All categories

2 years ago

14

SHORT ANSWER PROBLEM

1 answer:

CaHeK987 [17]2 years ago

3 0

Hello,

Janet Is wrong.
The common difference in the sequence is not -2.

The common quotient in the sequence is -2
-2/1=-2
4/-2=-2
-8/4=-2
...

You might be interested in

An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th

damaskus [11]

For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>

5 0

3 years ago

Please help please and thanks

Bingel [31]

This will help a lot if you go to desmos! Just graph the equation on there! It’s much easier to see on computer

7 0

3 years ago

Las casas del lado de la calle donde vive karina llenen todos los numeros pares la primera casa de la calle es el numero 200 y l

inysia [295]

Answer:

21

Step-by-step explanation:

count only the pair numbers between 200 and 240:

200, 202, 204, 206, 208, 210, 212, 214, 216, 218, 220, 222, 224, 226, 228, 230, 232, 234, 236, 238, 240

4 0

3 years ago

The diagrams show a right angled triangle and a rectangle.

Mrrafil [7]

Answer:

hope it helps you......................

8 0

2 years ago

Read 2 more answers

The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway

marysya [2.9K]

Answer:

The coordinate of the rest stop is: $(5,2.5)$

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

$(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

This gives:

$(x,y) = \frac{1}{2}(3+7,4+1)$

$(x,y) = \frac{1}{2}(10,5)$

Open bracket

$(x,y) = (5,2.5)$

Solving (b): Distance between the hotel and the stadium

We have:

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

The distance (d) is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$d = \sqrt{(3 - 7)^2 + (4 - 1)^2}$

$d = \sqrt{(-4)^2 + 3^2}$

$d = \sqrt{16 + 9}$

$d = \sqrt{25}$

$d =5$

From the question, we have:

$1\ unit = 6.4\ miles$

So:

$d =5 * 6.4\ miles$

$d =32\ miles$

3 0

2 years ago