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Viefleur [7K]
2 years ago
14

SHORT ANSWER PROBLEM

Mathematics
1 answer:
CaHeK987 [17]2 years ago
3 0
Hello,

Janet Is wrong.
The common difference in the sequence is  not -2.

The common quotient in the sequence is -2
-2/1=-2
4/-2=-2
-8/4=-2
...




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An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th
damaskus [11]
For the answer to the question above, <span> 
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
5 0
3 years ago
Please help please and thanks
Bingel [31]
This will help a lot if you go to desmos! Just graph the equation on there! It’s much easier to see on computer

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Las casas del lado de la calle donde vive karina llenen todos los numeros pares la primera casa de la calle es el numero 200 y l
inysia [295]

Answer:

21

Step-by-step explanation:

count only the pair numbers between 200 and 240:

200, 202, 204, 206, 208, 210, 212, 214, 216, 218, 220, 222, 224, 226, 228, 230, 232, 234, 236, 238, 240

4 0
3 years ago
The diagrams show a right angled triangle and a rectangle.
Mrrafil [7]

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8 0
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The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway
marysya [2.9K]

Answer:

The coordinate of the rest stop is: (5,2.5)

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

(x_1,y_1) = (3,4) --- Team hotel

(x_2,y_2) = (7,1) --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)

This gives:

(x,y) = \frac{1}{2}(3+7,4+1)

(x,y) = \frac{1}{2}(10,5)

Open bracket

(x,y) = (5,2.5)

Solving (b): Distance between the hotel and the stadium

We have:

(x_1,y_1) = (3,4) --- Team hotel

(x_2,y_2) = (7,1) --- Stadium

The distance (d) is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

d = \sqrt{(3 - 7)^2 + (4 - 1)^2}

d = \sqrt{(-4)^2 + 3^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

d =5

From the question, we have:

1\ unit = 6.4\ miles

So:

d =5 * 6.4\ miles

d =32\ miles

3 0
2 years ago
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