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GREYUIT [131]
3 years ago
10

Find the missing length indicated ​

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

x = 256

Step-by-step explanation:

Remark

Interesting question. Thanks for posting.

The small triangle has the height as the missing side.

Part One: Givens

a = 144

b = height = ?

c = 240

a^2 + b^2 = c^2

144^2 + b^2 = 240^2

20736 + b^2 = 57600                   Subtract 20736 from both sides

b^2 = 57600 - 20736

b^2 = 36864

√b^2 = √36864

b = 192

Solve for x

The relationship between the height (b) and 144 and x is

b^2 = 144 * x

36864 = 144x          Divide by 144

x = 256

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The Flintstone Construction Company delivers dirt and stone from local quarries to its construction sites. A new truck that was
schepotkina [342]

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depreciation to be allocated to A = 2800tons x $0.600 /ton

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Step-by-step explanation:

  • First calculate the amount of depreciation/ton
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4 years ago
If x2 mx m is a perfect-square trinomial, which equation must be true? x2 mx m = (x – 1)2 x2 mx m = (x 1)2 x2 mx m = (x 2)2 x2 m
Leno4ka [110]

An expression has numbers, variables, and mathematical operations. The equation that must be true so that x²+mx+m is a perfect square trinomial is x²+mx+m=(x+2)².

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

A perfect square trinomial is in the form (a+b)²=a²+b²+2ab. If we compare the perfect square trinomial x²+mx+m, we will get that the value of m should be such that it satisfies the equation m^2+2m. Since there is only one value that can satisfy this equation that is 2.

Therefore, the equation that must be true so that x²+mx+m is a perfect square trinomial is x²+mx+m=(x+2)².

Learn more about Expression:

brainly.com/question/13947055

6 0
2 years ago
What is the factored form of the expression?<br><br> d^2 = 36d + 324
Veseljchak [2.6K]

Answer:

(x-43.45)(x+7.45)=0

Step-by-step explanation:

We have the quadratic equation d^{2}=36d+324  i.e. d^{2}-36d-324=0

As, the roots of the quadratic equation ax^{2}+bx+c=0 are given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}.

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}, we get,

x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}

i.e. x=\frac{36\pm \sqrt{1296+1296}}{2}

i.e. x=\frac{36\pm \sqrt{2592}}{2}

i.e. x=\frac{36\pm 50.9}{2}

i.e. x=\frac{36+50.9}{2}  and x=\frac{36-50.9}{2}

i.e. x=\frac{86.9}{2}  and x=\frac{-14.9}{2}

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0

3 0
3 years ago
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