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2 years ago

Pls help me with this question

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

8 0

Answer:

D, C

Step-by-step explanation:

for part a, there is a negative slope with the graph shifted two units upwards

for part b, if you plug in C, you get an answer that works

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HELP ASSSAPPP WITH THIS QUESTION!!!

Gekata [30.6K]

D.d=24%
d.r=29%
d.t=53%
r.d=24%
r.r=24%
r.t=47%
t.d=47%
t.r=53%
t.t=100%
Just take the numbers and divide them over the total amount which in this caase is 51.

5 0

3 years ago

What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form. A. Show your work. B. Is the product of 2x -

VikaD [51]

Answer:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

No it is not.

Step-by-step explanation:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

(2x - 5) (3x² + 5x - 7)

= 2x(3x² + 5x - 7) -5(3x² + 5x - 7)

= 6x³ + 10x² - 14x -15x² - 25x +35

Collecting like terms

= 6x³ +10x² - 15x² - 14x - 25x +35

= 6x³ - 5x² - 39x + 35

In standard form

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

First we find the product of

5x - 2 and 3x² + 5x - 7?

(5x - 2) (3x² + 5x - 7)

5x(3x² + 5x - 7) -2(3x² + 5x - 7)

15x³ + 25x² - 35x - 6x² -10x + 14

Collect like terms

15x³+ 25x² - 6x² -35x - 10x + 14

15x³ + 19x² - 45x + 14 = 0

Hence, the product of 5x - 2 and 3x^2 + 5x - 7

= 15x³ + 19x² - 45x + 14 = 0

The product of 2x -5 and 3x^2 + 5x -7 = 6x³ - 5x² - 39x + 35 = 0

Comparing both products, we can see that

The product of 2x -5 and 3x^2 + 5x -7 ≠ the product of 5x - 2 and 3x^2 + 5x - 7

6 0

3 years ago

A population of 3000 people doubles in size every 10 years. Determine the population after 50 years.

RUDIKE [14]

Answer:

In 50 years Population is 96000 people.

Step-by-step explanation:

Let population be x

In the first 10 years

Population becomes 2x

In 20 years it becomes 4x

In 10n years it becomes 2^n x

Therefore

for n= 5

x = 3000

Population is 2⁵ (3000)

= 32(3000)

= 96000

Population becomes 96000

Hope it helps...

7 0

3 years ago

If Jesse cen make 41 jumps in 10 seconds how many can she do in five minutes.

Aleks04 [339]

1230 in five minutes Just multiply 6 * 41 to get to minutes format, then multiply by five make it five minutes. To get the second answer just divide it by two, which would make it 615.

Hope this helps!

6 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

6 0

3 years ago