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amm1812
3 years ago
6

Please help my answer is c, is this right!

Mathematics
1 answer:
Ray Of Light [21]3 years ago
6 0
I'm not sure how you got c but the way you would solve this is for every x on the line plot you would add that amount. You don't need to worry about 0 because 0 is nothing.
There are 3 X's at 1/4 so you would add 1/4+1/4+1/4=3/4. There are 2 X's at 1/2 so you would add 1/2+1/2=1. There are 2 X's at 3/4 so you would add 3/4+3/4=1.5. There is 1 X at 1 so it would just be 1. Then add all those together 3/4+1+1.5+1=4.25 or you could just add each X as you come across it on the number line like so:
0.25 + 0.25 + 0.25 + 0.5 + 0.5 + 0.75 + 0.75 + 1 = 4.25
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What is the slope of the line passing through the points (0, 4) and (6, 13)
skelet666 [1.2K]

Answer:

The slope is \frac{3}{2}

Step-by-step explanation:

Hi there!

We are given the points (0, 4) and (6, 13)

We want to find the slope of the line containing these two points

Slope (m) is the steepness of the line. When calculating from two points, you use the equation \frac{y_2-y_1}{x_2-x_1}, where (x_1, y_1) and (x_2, y_2) are points

Although we have what we need to find the slope, let's label the values of the points to avoid confusion and mistakes.

x_1=0\\y_1=4\\x_2=6\\y_2=13

Substitute these values into the equation

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{13-4}{6-0}

Subtract

m=\frac{9}{6}

Simplify

m=\frac{3}{2}

The slope of the line is 3/2

Hope this helps!

See more on calculating slopes from 2 points here: brainly.com/question/26738734

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2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C
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\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

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