Please help my answer is c, is this right!
1 answer:
I'm not sure how you got c but the way you would solve this is for every x on the line plot you would add that amount. You don't need to worry about 0 because 0 is nothing.
There are 3 X's at 1/4 so you would add 1/4+1/4+1/4=3/4. There are 2 X's at 1/2 so you would add 1/2+1/2=1. There are 2 X's at 3/4 so you would add 3/4+3/4=1.5. There is 1 X at 1 so it would just be 1. Then add all those together 3/4+1+1.5+1=4.25 or you could just add each X as you come across it on the number line like so:
There are 3 X's at 1/4 so you would add 1/4+1/4+1/4=3/4. There are 2 X's at 1/2 so you would add 1/2+1/2=1. There are 2 X's at 3/4 so you would add 3/4+3/4=1.5. There is 1 X at 1 so it would just be 1. Then add all those together 3/4+1+1.5+1=4.25 or you could just add each X as you come across it on the number line like so:
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Answer:
The calculated value t = 1.76 < 2.131 at 0.05 level of significance
Null hypothesis is accepted
The manufacturer’s claim is greater than 560 bags per hour
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given sample size 'n' =16
Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.
mean of the Population 'μ' = 560
Mean of the sample Χ⁻ = 538
sample standard deviation' S' = 50
<em><u>Null hypothesis</u></em><em>:H₀:μ > 560</em>
<em><u>Alternative Hypothesis</u></em><em>:H₁ : :μ < 560 (left tailed test)</em>
<em>Test statistic</em>
|t| = |-1.76| = 1.76
<em>Degrees of freedom </em>
<em>γ = n-1 =16-1 =15</em>
<em><u>Conclusion</u></em>:-
The calculated value t = 1.76 < 2.131 at 0.05 level of significance
Null hypothesis is accepted
The manufacturer’s claim is greater than 560 bags per hour