Answer:
We conclude that the Pennsylvania school district have an IQ higher than the average of 101.5
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 101.5
Sample mean,
= 106.4
Sample size, n = 30
Alpha, α = 0.05
Population standard deviation, σ = 15
First, we design the null and the alternate hypothesis
We use one-tailed z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and accept the alternate hypothesis.
Thus, we conclude that the Pennsylvania school district have an IQ higher than the average of 101.5
Step-by-step explanation:
14)
Simplifying
3m + 5 = 4m -10
Reorder the terms:
5 + 3m = 4m -10
Reorder the terms:
5 + 3m = -10 + 4m
Solving
5 + 3m = -10 + 4m
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '-4m' to each side of the equation.
5 + 3m + -4m = -10 + 4m + -4m
Combine like terms: 3m + -4m = -1m
5 + -1m = -10 + 4m + -4m
Combine like terms: 4m + -4m = 0
5 + -1m = -10 + 0
5 + -1m = -10
Add '-5' to each side of the equation.
5 + -5 + -1m = -10 + -5
Combine like terms: 5 + -5 = 0
0 + -1m = -10 + -5
-1m = -10 + -5
Combine like terms: -10 + -5 = -15
-1m = -15
Divide each side by '-1'.
m = 15
Simplifying
m = 15
(thank to <em>geteasysolution</em> . com
15)
xy+yz=xz
a+a+8=50
2a=42
a=21
a+8=29
Yeth you are right.......
Answer:
115
Step-by-step explanation:
20% is one fifth. If Mary has one fifth fewer than Susan, then she has 4 fifths of what Susan has. So 92 is 4 fifths of some number.
To find out what one fifth is, you can divide 92 by 4 because it is four fifths.
92/4 = 23
So one fifth of the number of blouses Susan has is 23. Now you can multiply 23 by 5 to get the total number of blouses Susan has.
23 * 5 = 115
That would be the SSS postulate.